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Norma-Jean [14]

3 years ago

6

The width of a soccer field should be 60% of its length. Write and simplify an expression for the perimeter of a soccer field wi

th a length of x feet.

1 answer:

iogann1982 [59]3 years ago

4 0

Answer:

here you go

Step-by-step explanation:

W = (0.6) L

P = 2 ( L + W )

P = 2 [ L + (0.6) L ]

P = 2 ( 1.6 L )

P = (3.2) L

P = (3.2) x

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At Penny's Pie Shop, it costs $4 for <br> 1<br> 4<br> of a pie. What is the cost of a whole pie

sergey [27]

Answer:

16

Step-by-step explanation:

1/4 pie=4

2/4 pie= 8

3/4 pie= 12

4/4pie= 16

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3 years ago

A computer chip has dimensions of 8mm x 8mm. the scale drawing shows 4cm by 4cm. the answer is 1cm represents 2mm but I don't kn

Andru [333]

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6 0

3 years ago

A ramp has a rise of 10 feet and run of 50 feet find the slope

Goshia [24]

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7 0

3 years ago

Read 2 more answers

A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactl

Andrew [12]

Answer: $\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}$ or $\dfrac{228}{91885}$ .

Step-by-step explanation:

Given : A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards.

The total number of cards in a deck 52

Number of faces cards in a deck = 12

Number of cards not face cards = 40

The total number of combinations of drawing 9 cards out of 52 cards = $^{52}C_9$

Now , the combination of 9 cards such that exactly 6 of them are face cards = $^{12}C_{6}\times^{40}C_3$

Now , the probability that the hand contains exactly 6 face cards will be :-

$\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}$

$=\dfrac{\dfrac{12!}{6!6!}\times\dfrac{40!}{3!37!}}{\dfrac{52!}{9!\times43!}}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{228}{91885}$

Hence, the probability that the hand contains exactly 6 face cards. is $\dfrac{228}{91885}$ .

6 0

3 years ago

Please help me fast I still nee to finish 2 more ixl's by monday!!!!

sleet_krkn [62]

Answer:No

Step-by-step explanation:

Given system of equation is:

2x + 3 = y

2x + y = 15

To check whether (2,7) is solution to this system or not, we will put x=2 and y=7 in both equations.

Putting x=2 and y=7 in Eqn 1

2(2) + 3 = 7

4 + 3 = 7

7 = 7

Thus the ordered pair satisfies the equation

Putting x=2 and y=7 in Eqn 2

2(2) + 7 = 15

4 + 7 = 15

11 ≠ 15

The ordered pair do not satisfy the second equation.

Hence,

(2,7) is not a solution to the given system of equations.

3 0

3 years ago