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2 years ago

Is 619 good on an I-ready test??

Mathematics

2 answers:

lesya [120]2 years ago

8 0

That’s great but math or reading and what grade

Sever21 [200]2 years ago

4 0

Yeah I’m pretty sure

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Which expression represents the difference of (5x-3y) and (8x+8y)?

artcher [175]

Given:

The expressions are:

$(5x-3y)$ and $(8x+8y)$

To find:

The difference of $(5x-3y)$ and $(8x+8y)$ .

Solution:

Difference of $(5x-3y)$ and $(8x+8y)$ is written as:

$Difference=(5x-3y)-(8x+8y)$

On simplification, we get

$Difference=5x-3y-8x-8y$

$Difference=(5x-8x)+(-3y-8y)$

$Difference=-3x-11y$

Therefore, the difference of $(5x-3y)$ and $(8x+8y)$ is $-3x-11y$ .

6 0

3 years ago

(x/x+3)-(8/x+2)=(-13x-6)/(x^2+5x+6)

Fed [463]

Answer:

x = -9

x = 2

Step-by-step explanation:

Given:

$\dfrac{x}{x+3}-\dfrac{8}{x+2}=\dfrac{-13x-6}{x^2+5x+6}$

First, note that

$x^2+5x+6=x^2+2x+3x+6=x(x+2)+3(x+2)=(x+2)(x+3)$

Since $x+2$ and $x+3$ stay in the denominator, then

$x\neq -2\ \text{and}\ x\neq -3$

Now add two fractions which stay in the left part. The common denominator is $(x+2)(x+3),$ so multiply the numerator of the first fraction by $(x+2)$ and the numerator of the second fraction by $(x+3)$ and subtract them in the numerator:

$\dfrac{x}{x+3}-\dfrac{8}{x+2}=\dfrac{-13x-6}{(x+2)(x+3)}\\ \\\dfrac{x(x+2)-8(x+3)}{(x+2)(x+3)}=\dfrac{-13x-6}{(x+2)(x+3)}\\ \\x(x+2)-8(x+3)=-13x-6\\ \\x^2+2x-8x-24=-13x-6\\ \\x^2+2x-8x+13x-24+6=0\\ \\x^2+7x-18=0\\ \\x^2+9x-2x-18=0\\ \\x(x+9)-2(x+9)=0\\ \\(x+9)(x-2)=0\\ \\x+9=0\ \text{or}\ x-2=0\\ \\x=-9\ \text{or}\ x=2$