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kow [346]
3 years ago
5

Which method is the most efficient method to use to solve x^2+6x-7=0?

Business
2 answers:
sweet-ann [11.9K]3 years ago
7 0
(x+7)(x-1) = 0 ^x^2 + 6x - 7 = 0x               7x              -1
Its really easy if you think it this way.

Jlenok [28]3 years ago
3 0
X² + 6x - 7 = 0? Um, I usually write that down, but the answer would be x = 7 and x = -1. Since it is set equal to zero, you will have two answers to this equation.
The first term is, x2 its coefficient is 1 .
The middle term is, -6x its coefficient is -6 .
The last term, "the constant", is -7

1 • -7 = -7
-7 + 1 = -6
x2 - 7x + 1x - 7
1 • (x-7)
(x+1) • (x-7)
(x + 1) • (x - 7) = 0
x+1 = 0 therefore x = -1
and
x-7 = 0 therefore x = 7


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