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Kryger [21]
3 years ago
9

Triangles have a total of 180°. Use the triangle below to determine the the value of X.

Mathematics
2 answers:
blsea [12.9K]3 years ago
5 0
I will need to see the triangle
Lapatulllka [165]3 years ago
5 0

Answer:

We can't tell there is no information about the triangle

Step-by-step explanation:

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I need help with this please
enyata [817]

Answer:¿Qué es lo contrario de estos estadistas?

Step-by-step explanation:

What is the opposite of these statesment

5 0
3 years ago
Find the next three terms of the arithmetic sequence.<br> a) 9, 12, 15, ... b) 288, 252, 216, ...
Harlamova29_29 [7]

Answer:

a) 18,21,24

b)180, 144, 108

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
3.The side of a square frame is (2b - 1) inches. Find its area.
sweet-ann [11.9K]

Answer:

Step-by-step explanation:

(a - b)² = a² + 2ab + b²

Area of square frame =side²

                                   = (2b - 1)²

                                   = (2b)² - 2*2b * 1 + 1²

                                   = 4b² - 4b + 1

5 0
2 years ago
Mrs.cyan paid $105 for flower boxes. each flower box cost $7. how many flowers did she buy
Ede4ka [16]

Answer:

15

Step-by-step explanation:

To find how many she bought, we have to divide. So we do 105/7=15.

8 0
2 years ago
Read 2 more answers
Please show work and thank youuu
Assoli18 [71]

Answer:  6\sqrt{3}

======================================================

Explanation:

Method 1

We can use the pythagorean theorem to find x.

a^2+b^2 = c^2\\\\6^2+x^2 = 12^2\\\\36+x^2 = 144\\\\x^2 = 144-36\\\\x^2 = 108\\\\x = \sqrt{108}\\\\x = \sqrt{36*3}\\\\x = \sqrt{36}*\sqrt{3}\\\\x = 6\sqrt{3}\\\\

-----------------------------------

Method 2

Use the sine ratio to find x. You'll need a reference sheet or the unit circle, or simply memorize that sin(60) = sqrt(3)/2

\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(60^{\circ}) = \frac{x}{12}\\\\\frac{\sqrt{3}}{2} = \frac{x}{12}\\\\x = 12*\frac{\sqrt{3}}{2}\\\\x = 6\sqrt{3}\\\\

-----------------------------------

Method 3

Similar to the previous method, but we'll use tangent this time.

Use a reference sheet, unit circle, or memorize that tan(60) = sqrt(3)

\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(60^{\circ}) = \frac{x}{6}\\\\\sqrt{3} = \frac{x}{6}\\\\x = 6\sqrt{3}\\\\

-----------------------------------

Method 4

This is a 30-60-90 triangle. In other words, the angles are 30 degrees, 60 degrees, and 90 degrees.

Because of this special type of triangle, we know that the long leg is exactly sqrt(3) times that of the short leg.

\text{long leg} = (\text{short leg})*\sqrt{3}\\\\x = 6\sqrt{3}\\\\

The short leg is always opposite the smallest angle (30 degrees).

3 0
2 years ago
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