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2 years ago

Is B equal to C in this geometry problem? I just need to know, that and then I can solve the rest.

Mathematics

1 answer:

Arada [10]2 years ago

3 0

In the right angled triangle ACD shown with isosceles triangle ABC and ADC, AB = AC = AD

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

A triangle is a polygon that has three sides and three angles. Types of triangles are<em> isosceles, equilateral and scalene</em>.

In the diagram shown:

AB = AC = AD

In the right angled triangle ACD shown with isosceles triangle ABC and ADC, AB = AC = AD

Find out more on equation at: brainly.com/question/2972832

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PLEASE HELP “ solve the following any quality and write the solution in set form”

Veronika [31]

Answer:

14 and 16

Step-by-step explanation:

A number used in the mathematical operation of addition (e.g., 6 + 8 = 14, ... K-5 Definitions of Math Terms. 15 remainder. The number left over is 14-16

3 0

2 years ago

Which expression has the same value as 9,381x5?

elena55 [62]

Answer: C) (9000x5) + (300x5) + (8~5) + (1x5)

Step-by-step explanation:

First Find what 9381 times 5 is.

9381x5=46108

Now Find out all the equations.

9000x5= 45000

300x5=1500

8-5=3

1*5=5

Now Add it all up.

45000+1500=46100

46100+3=46103

46103+5=46108

So, Your Answer is (C)

Your Welcome.

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2 years ago

PEASE PLEASE HELP & EXPLAIN

Vikki [24]

Answer:the answer is NO.

Step-by-step explanation:

Because the number 9, repeats itself in the domain.

7 0

3 years ago

In parallelogram DEFG, DH equals X +3, HF equals 3Y, GH equals 2X -5 and HE equals 5Y plus to find the values of X and Y

daser333 [38]

The values of X and Y are 30 and 11 respectively

<h3>How to determine the values of X and Y?</h3>

The figure that represents the complete question is added as an attachment

The given parameters are:

DH = X +3

HF = 3Y

GH = 2X -5

HE = 5Y

From the attached parallelogram, we have:

DH = HF

GH = HE

Substitute the known values in the above equation

X + 3 = 3Y

2X - 5 = 5Y

Make X the subject in X + 3 = 3Y

X = 3Y - 3

Substitute X = 3Y - 3 in 2X - 5 = 5Y

2(3Y - 3) - 5 = 5Y

Expand

6Y - 6 - 5 = 5Y

Evaluate the like terms

Y = 11

Substitute Y = 11 in X = 3Y - 3

X = 3*11 - 3

Evaluate

X = 30

Hence, the values of X and Y are 30 and 11 respectively