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Charra [1.4K]
3 years ago
11

Please help me, please

Mathematics
1 answer:
Fudgin [204]3 years ago
6 0

Answer:

C.

Step-by-step explanation:

C, because he can find out how many people wanted 12 bags of apples and who wanted more/less.

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Help me do this please
Leona [35]

Answer:

145

Step-by-step explanation:

85+60

6 0
3 years ago
Algebra ,, will mark brainliest!!
Viktor [21]

Answer:

B

Step-by-step explanation:

(1 1/2,-2)

solve for x and get 1 1/2

solve for y and get -2

7 0
2 years ago
An oil drilling company drills the same distance each day for 5 days. They started at an elevation of 121.175 feet and ended at
nirvana33 [79]

Answer:

x=\dfrac{|-246.875-121.175|}{5}

Step-by-step explanation:

Given that:

Same distance is drilled by the oil drilling company for 5 days.

Initial elevation = 121.175 feet

Final elevation = -246.875 feet

To find:

The equation to find the value of x i.e. the distance drilled each day?

Solution:

To find the distance drilled each day, we need to divide the total distance drilled with the number of days taken to drill the total distance.

Total distance drilled can be found by subtracting the initial elevation from the final elevation and taking modulus because distance can not be negative.

Total distance drilled = | Final elevation - Initial elevation |

Total distance drilled = | -246.875 - 121.175 |

Therefore, we can write the expression as:

x=\dfrac{|-246.875-121.175|}{5}

\Rightarrow x=\dfrac{|-368.05 |}{5} =73.61\ ft/day

3 0
3 years ago
Terry selected two cards. The sum of her card is -10. Can one of the cards be positive and the other be negative.
Luda [366]
No because if you subtract -10-2 you get -12 and you only have a negative answer
6 0
4 years ago
In 2002, Tim was twice as old as Sue. In 1997 the sum of their ages was 32. In what year will Sue's age be three-fourths Tim's a
xxMikexx [17]

Answer:

Year 2030.

Step-by-step explanation

In 1997, Let Tim's age = <em>X</em> years

In 1997, Let Sue's age = <em>Y</em> years

After 5 years in 2002, Tim's age = (<em>X+ 5) </em>years

After 5 years in 2002, Sue's age = <em>(Y + 5)</em> years

Now, According to question,

<em>X </em>+ <em>Y</em> = 32    (sum of their ages) .......(1)

<em>Y </em>= 32 -<em> X</em>

(X + 5) = 2 (Y + 5) .......(2)

Substituting the value of <em>Y</em> in (2)

<em>X </em>+ 5 = 2 (32 - <em>X </em>+ 5)

<em>X </em>+ 5 = 2 (37 - <em>X </em>)

<em>X </em>+ 5 = 74 - 2<em>X </em>

3<em>X </em>=<em> </em>69

<em>X </em>= 69/3 = 23

Now ∵<em> Y</em> = 32 - <em>X  </em>and<em> X = </em>23

∴ <em>Y</em> = 32 - 23 = 9

So, In 1997, Tim's age = 23 years and Sue's age = 9 years.

Let the year in which Sue's age will be three-fourth times of Tim's age be t.

Sue's age after<em> t </em>years = (9 +<em> t) </em>years.

Tim's age after<em> t</em> years = (23 + <em>t</em>) years

According to question,

(9 + t) = \frac{3}{4} \times(23 + t)

4 (9 + t) = 3 (23 + t)

36 + 4t = 69 + 3t

<em>4t - 3t = 69 - 36</em>

<em>t = 33</em>

The Year in which Sue's age will be three-fourth times of Tim's age is:

= (1997 + 33) = 2030.

4 0
4 years ago
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