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weeeeeb [17]
3 years ago
12

2x + 20 I need answers

Mathematics
1 answer:
ivann1987 [24]3 years ago
4 0

Answer:

20 is the answer

Step-by-step explanation:

2x0=0+20=20

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:( need help pls pls pls pla
Alenkasestr [34]

Answer:

216

Step-by-step explanation:

7 0
3 years ago
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The equation for velocity is v = distance time . Evaluate the velocity of an object that travels 15 meters in 2.5 seconds.
kvasek [131]

Answer:

What is acceleration?

Imagine you are playing golf, and you’ve just set up the golf ball on the tee. You test your grip, take a few practice swings, and peer into the distance at the flag pole marking the first hole for the course. Your wise golf ball guru (who happens to also teach physics) tells you to “Be the ball, young grasshopper.” So you close your eyes and picture the distance the ball must travel. “Yes, young earthworm”, your sensei says, “that distance you see is the displacement you must achieve, displacement is the change in position from one place to another.”

Step-by-step explanation:

7 0
3 years ago
Where does the graph of the line 3x-4y=12 intersect at the y-axis
yarga [219]

Answer:

This line intersects the y-axis at (0, -3)

Step-by-step explanation:

<u>Step 1:  Set x to 0 to find where the y-int is </u>

3(0) - 4y = 12

-4y / -4 = 12 / -4

y = -3

Answer: This line intersects the y-axis at (0, -3)

8 0
3 years ago
What is the vertex of the function x2 - 6x + 8 = 0?
RUDIKE [14]

<u>Answer: </u>

The vertex of the function \bold{x^{2} -6 x + 8 = 0}is (h,k) = (3 , -1)

<u>Solution: </u>

The vertex form of quadratic equation is generally given as,

f(x) = a(x - h)^{2} + k

Where h,k is the vertex of the parabola.

From question, given that x^{2}-6 x+8=0 .

we have to find the vertex of the function.

Let us first convert the given quadratic equation to vertex form (eqn 1)

x^{2}-6 x+8=0

x^{2}-6 x=-8

By adding “9” on both sides of equation, we get

x^{2}-6 x+9=-8+9

x^{2}-6 x+9=1

By using the identity (a-b)^{2}=a^{2}-2 a b+b^{2} ,the right hand side of above equation becomes,

(x-3)^{2}=1

(x-3)^{2}-1=0

Now,the equation (x-3)^{2}-1=0 is of the vertex form.

By comparing (x-3)^{2}-1=0 with a(x-h)^{2}+k

we get the values of (h,k)

a = 1; h = 3; k = -1

hence the vertex of the function x^{2}-6 x+8=0 is (h,k) = (3 , -1)

5 0
3 years ago
Can you answer this problem?
Mama L [17]
(gof)(3) = g(f(3))
so
f(3) = -2(3) + 8 = 2
g(f(3)) = 5(2) = 10
answer
C. 10
4 0
3 years ago
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