Answer:
4y²−38y−20
Step-by-step explanation:
(y−10)(4y+2)
=(y+−10)(4y+2)
=(y)(4y)+(y)(2)+(−10)(4y)+(−10)(2)
=4y²+2y−40y−20
=4y²−38y−20
please mark me brainliest!
Hey!
For 45-45-90 triangles you use you use the formula L(on the square root of)2
L represents the legs.
So you plug in
3(on the square root of)2 times (the square root of)2
You multiply the square roots to get
3(on the square root of)4
You simplify the square root of 4 to 2
So 3 times 2 = 6
So 6 is the answer
Hope this helped!
Answer:
60
Step-by-step explanation:
Answer:
Part A: See the image attached. The angle between the radius and the chord will always be 90 degree if the radius is perpendicular to the chord
Part B: There are many ways to prove this and here is mine
Prove OC is perpendicular to AB
We know that ΔAEC≅AED by SSS criteria (SSS criteria is when all three sides of a triangle is equal making them congruent)
to prove this that they apply to the SSS criteria:
m∠ADO=m∠BDO
m∠ADO=90°=m∠BDO
Part C: See the image attached. A radius is perpendicular to a chord when the chord is equally divided in half by the radius.
Part D: There are many ways to prove this and here is mine
Prove OC is perpendicular to AB
AO=BO because AO and BO are both radii
OD≅OD by reflexive theorem
ΔADO≅ΔBDO because they are both right triangle with the hypotenuse and a side
AB≅BC means that OC is perpendicular to AB
If you are still confused then I recommend watching these vdos by khan academy about proving perpendicular radius bisector: https://youtu.be/2NgzruZ4_5c
https://youtu.be/TgDk06Qayxw
Hope this helped bye:)