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sammy [17]
3 years ago
5

If my problem is 9(Xsquared) + 8x -1, How do I simplify this?

Mathematics
1 answer:
Elden [556K]3 years ago
6 0
(X-9)(X-1)
Is simplifyed
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What is (y-10)(4y+2)?
AleksandrR [38]

Answer:

4y²−38y−20

Step-by-step explanation:

(y−10)(4y+2)

=(y+−10)(4y+2)

=(y)(4y)+(y)(2)+(−10)(4y)+(−10)(2)

=4y²+2y−40y−20

=4y²−38y−20

please mark me brainliest!

8 0
3 years ago
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you drink one fourth of a pitcher of Kool-Aid your friend drinks 7/12 of the pitcher what fraction of the pitcher do you and you
ASHA 777 [7]
1/4 is equal to 3/12 and 3/12 + 7/12 = 10/12 or 5/6
3 0
3 years ago
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Find the length of the variable.
Dafna1 [17]
Hey!
For 45-45-90 triangles you use you use the formula L(on the square root of)2
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So you plug in
3(on the square root of)2 times (the square root of)2
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3(on the square root of)4
You simplify the square root of 4 to 2
So 3 times 2 = 6
So 6 is the answer
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5 0
3 years ago
The cost of oranges is $1. What is the cost of 5 dozen oranges.
lara31 [8.8K]

Answer:

60

Step-by-step explanation:

6 0
3 years ago
Construct a circle of any radius, and draw a chord on it. Then construct the radius of the circle that bisects the chord. Measur
Nady [450]

Answer:

Part A: See the image attached. The angle between the radius and the chord will always be 90 degree if the radius is perpendicular to the chord

Part B: There are many ways to prove this and here is mine

Prove OC is perpendicular to AB

We know that ΔAEC≅AED by SSS criteria (SSS criteria is when all three sides of a triangle is equal making them congruent)

to prove this that they apply to the SSS criteria:

m∠ADO=m∠BDO

m∠ADO=90°=m∠BDO

Part C: See the image attached. A radius is perpendicular to a chord when the chord is equally divided in half by the radius.

Part D: There are many ways to prove this and here is mine

Prove OC is perpendicular to AB

AO=BO because AO and BO are both radii

OD≅OD by reflexive theorem

ΔADO≅ΔBDO because they are both right triangle with the hypotenuse and a side

AB≅BC means that OC is perpendicular to AB

If you are still confused then I recommend watching these vdos by khan academy about proving perpendicular radius bisector: https://youtu.be/2NgzruZ4_5c

https://youtu.be/TgDk06Qayxw

Hope this helped bye:)

4 0
3 years ago
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