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kumpel [21]
3 years ago
8

I said SAS but am not sure because the base could be two equal sides as well so could someone help me out?

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
4 0

Answer: C) SAS is correct

Check out the diagram below.

We're given BA = BC as shown in red.

The congruent angles are shown in blue. The larger angle is bisected into smaller equal halves.

The red segments are congruent by the reflexive property.

The angles mentioned are between the sides mentioned, so that's why we can use SAS.

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Please solve this for me
olga_2 [115]
15/5 is 3

So then you change the equation to be 12=15z-3 ( don’t forgot the negative sign)

Move the constant to the right side and change the sign

-15z= -3 -12

-3-12 is -15

Divide -15z= -15

Your final answer will be z= 1
5 0
3 years ago
Help plz (problly easy for you)
PolarNik [594]

The second option: 4x² - x + 1

All you have to do is add the like terms:

3x² + x² = 4x²

4x - 5x = -x

-2 + 3 = 1

Combine all the results and you will get your solution!

6 0
3 years ago
On Friday, 3/5 of the students wore blue shirts and 1/4 of the students wore white shirts. What fraction of the students wore ei
velikii [3]
Since 3/5 of the students wore blue shirts and 1/4 of the students wore white shirts, you need to find the Total of 3/5 and 1/4.
First, step find a common denominator for both fractions
EXAMPLE: 3/5+1/4=Total 3/5 becomes 12/20 and 1/4 becomes 5/20.
Second, notice that both fractions now have the same denominator, now you can find the sum of both fractions which is 17/20
Finally, you need to check if the fraction can be SIMPLIFIED if not then the fraction is already im simplest form.
THE ANSWER: 17/20 of students wore either a blue or white shirt on Friday

6 0
3 years ago
If y=e5t is a solution to the differential equation
a_sh-v [17]

Answer:

k = 30, y(t) = C_1e^{5t}+C_2e^{6t}

Step-by-step explanation:

Since y=e^{5t} is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}

Then, replacing the derivatives in the equation we have:

25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0

Since e^{5t} is a positive function, we have that

25-55+k = 0 \rightarrow k = 30.

Now, consider a general solution y(t) = Ae^{rt}, A \in \mathbb{R}, then, by calculating the derivatives and replacing them in the equation, we get

Ae^{rt}(r^2-11r+30)=0

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

y(t) = C_1e^{5t}+C_2e^{6t}

8 0
3 years ago
A function is shown in the table:
Ipatiy [6.2K]

Answer:

The function is increasing from x = -2 to x = -1.

Step-by-step explanation:

The graph starts at -2 and is increasing by 1. it would not be "The function is increasing from x = 0 to x = 1" because it does not start at 0. it starts at -2. even though they both increase by 1, the starting point answer is always the best option.

8 0
3 years ago
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