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juin [17]
3 years ago
5

10 points!!! What is sqr root 12x^8/ sqr root 3x^2 in simplest form

Mathematics
2 answers:
marta [7]3 years ago
8 0

Answer:

2 x^3

Step-by-step explanation:

sqrt(12 x^8)/ sqrt(3x^2)

combine into 1 term

sqrt(12x^8/3x^2)

when dividing exponents with the same base, we subtract

sqrt(12/3  x^(8-2))

sqrt(4 x^6)

sqrt(4)  sqrt(x^6)

2 x^3

boyakko [2]3 years ago
8 0

Answer:

2x^3

Step-by-step explanation:

\frac{\sqrt{12x^8}}{\sqrt{3x^2}}

Both top and bottom have square root . We can take square root in common

\sqrt{\frac{12x^8}{3x^2} }

simplify the exponent using exponential property

a^m / a^n = a^{m-n}, subtract the exponents

\sqrt{\frac{12x^8}{3x^2} }

\sqrt{4x^6}

\sqrt{4} =2

\sqrt{x^6} =\sqrt{x^2 \cdot x^2 \cdot x^2} =x^3

\sqrt{4x^6}=2x^3

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Step-by-step explanation:

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Answer:


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