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horrorfan [7]
3 years ago
11

Find the side length s of the square. Please help

Mathematics
1 answer:
KatRina [158]3 years ago
6 0

6/7 !!!! the answer is 6/7

Step-by-step explanation:

pls follow me

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S_A_V [24]
There are 95 ounces and 5.9375 pounds.
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3 years ago
PLEASE HELP 8th GRADE MATH QUESTION OVER HERE!!!
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The side AB measures option 2. \sqrt{20}} units long.

Step-by-step explanation:

Step 1:

The coordinates of the given triangle ABC are A (4, 5), B (2, 1), and C (4, 1).

The sides of the triangle are AB, BC, and CA. We need to determine the length of AB.

To calculate the distance between two points, we use the formula d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}.

where (x_{1},y_{1}) are the coordinates of the first point and (x_{2},y_{2}) are the coordinates of the second point.

Step 2:

For A (4, 5) and B (2, 1), (x_{1},y_{1}) = (4, 5) and (x_{2},y_{2}) = (2, 1). Substituting these values in the distance formula, we get

d=\sqrt{\left(2-4\right)^{2}+\left(1-5}\right)^{2}} = \sqrt{\left(2\right)^{2}+\left(4}\right)^{2}}=\sqrt{20}}.

So the side AB measures \sqrt{20}} units long which is the second option.

6 0
2 years ago
Ixl/Signin/Eli whitney Help please
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3 years ago
Find the domain of ( (a+b/b) − (a/a+b))÷( (a+b/a) − (b/a+b) )
Alexandra [31]

Answer:

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, a=-b

Step-by-step explanation:

The domain refers to values for which the expression is defined.

This implies that, the denominators are not equal to zero.

(\frac{a + b}{b} -  \frac{a}{a + b}) \div ( \frac{a + b}{a} -  \frac{b}{a + b})

(\frac{(a + b)(a + b)-ab}{b(a + b)})\div(\frac{(a + b)(a + b)-ab}{a(a + b)})

\frac{(a + b)(a + b)-ab}{b(a + b)} \times\frac{a(a + b)}{(a + b)(a + b)-ab}

\implies \frac{a}{b}

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, and a=-b

7 0
3 years ago
Read 2 more answers
Factorise 12u-uv please help lol
max2010maxim [7]

Answer:

u(12-v)

Step-by-step explanation:

12u and -uv both have a factor of <em>u </em>in common, so we can pull it out to give us the factored expression u(12-v).

<em>Note on factoring:</em>

<em>Remember, it's just using the distributive property in reverse! We can get our original expression back by distributing the u to the 12 and the -v.</em>

6 0
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