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lbvjy [14]
3 years ago
8

One painter can finish a certain job 5 hours before another painter who is doing the same job. When they work together they can

finish this job in 6 hours. How long does it take for each painter to do the job by himself?
Mathematics
1 answer:
Whitepunk [10]3 years ago
5 0

Answer:

A (painter 1) = 10 hours

B (painter 2) = 15 hours

Step-by-step explanation:

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I don’t know how to do it can someone help me?
frozen [14]

Answer:f(g(0))= 1/5

              g(f(0))= 7

Step-by-step explanation:

for f(g(0))=you solve for g(x) but you plug in 0 for x so g(0)= 8(0)+3

                                                                                                    =3

 so now you plug in the answer of the function of g(x) witch is 3 and plug it in as the x for F(x) so f(3)= 1/(3)+2

                                     = 1/5

so f(g(0)) is equal to 1/5

Now for G(f(0)) you solve for f(x) by pluging 0 for x so F(0)= 1/(0)+2

                                                                                               =1/2

now you plug in 1/2 for the x of g(x) so g(1/2)= 8(1/2)+3

                                                                         = 4+3

                                                                         =7

so g(f(0)) is equal to 7

Hope this helps:)

3 0
3 years ago
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anygoal [31]

Answer:

(1. 5

(2. 180

(3. 900

(4. 5180=900

Step-by-step explanation:

5 0
3 years ago
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