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3 years ago

Find the area of a square with side length 4/5 yard.

Mathematics

2 answers:

melisa1 [442]3 years ago

8 0

Answer:

Step-by-step explanation:

The area of a square is the side squared.

A=s^2, if s=4/5 then

A=(4/5)^2

A=16/25

So the area is 16/25 yd^2 as a fraction or 0.64 yd^2 as a decimal.

BigorU [14]3 years ago

6 0

Answer:

side length = 0.8 yards

area = side length^2= 0.8^2 = 0.64 or 64/100

Step-by-step explanation:

hope that helped

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Find the mean, meadian, mode and range for each set of data 6, 9, 2, 4, 3, 6, 5

Helga [31]

Mean: Add up the numbers and divide the sum by the number of values in the set.

6 + 9 + 2 + 4 + 3 + 6 + 5 = 35

35 / 7 = 5

Median: Sort the set from the smallest value to the largest value and select the number in the middle. If the count of the set if even, then select the two middle values and take their mean average.

2, 3, 4, 5, 6, 6, 9

So, the median average is 5.

Mode: What number appears the most frequently?

The mode of the set is 6 because it appears twice.

Range: Sort the set by ascending order and take the smallest value and subtract that from the largest value in the set.

9 - 2 = 7

The range is 7.

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3 years ago

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3xy + x = -29 Literal Equations! Solve for X. Show solution please! Thanks in advance!

frosja888 [35]

3xy+x=-29
-3xy -3xy
x= -3xy-29

4 0

3 years ago

Solve the equation by completing the square. ^x2- 12x = -28

Olegator [25]

x^2 -12 x = -28

(-12/2) ^ 2 =36

x^2 -12 x + 36 = -28 + 36

x^2 -12x + 36 = 8

(x-6)^2 = 8

take the square root of each side

x-6 = sqrt (8) x-6 = -sqrt (8)

you get a positive and a negative when taking the square root

x= 6 + sqrt (8)

x = 6 - sqrt (8)

sqrt (8) = 2 sqrt (2)

x= 6 + 2 sqrt (2)

x = 6 - 2 sqrt (2)

Answer:

x= 6 + 2 sqrt (2)

x = 6 - 2 sqrt (2)

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3 years ago

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A rhombus has a side length equal to one of the diagonals. The other diagonal is 4cm longer. Find the area of the rhombus.

klasskru [66]

Answer:

The area of the rhombus is 25.83 cm².

Step-by-step explanation:

The area of a rhombus is given by:

$A = \frac{d_{1} \times d_{2}}{2}$

Where:

d₁: is one diagonal

d₂: is the other diagonal = d₁ + 4 cm

We know that one side length of the rhombus is equal to d₁. We can imagine a right triangle inside the rhombus, with the following dimensions:

h: hypotenuse of the right triangle

a: one side of the right triangle

b: is the other side of the right triangle

From the above we know that:

h = d₁

$a = \frac{d_{2}}{2} = \frac{d_{1} + 4}{2}$

$b = \frac{d_{1}}{2}$

We can find d₁ with Pitagoras:

$h^{2} = a^{2} + b^{2}$

$d_{1}^{2} = (\frac{d_{1} + 4}{2})^{2} + (\frac{d_{1}}{2})^{2}$

$d_{1}^{2} = \frac{1}{4}(d_{1}^{2} + 8d_{1} + 16 + d_{1}^{2})$

By solving the above quadratic equation for d₁ and taking the positive solution we have:

$d_{1} = 5.46 cm$

So, d₂ is:

$d_{2} = d_{1} + 4 = 5.46 cm + 4 cm = 9.46 cm$

Now, we can find the area:

$A = \frac{d_{1} \times d_{2}}{2} = \frac{5.46 cm \times 9.46 cm}{2} = 25.83 cm^{2}$

Therefore, the area of the rhombus is 25.83 cm².

I hope it helps you!

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3 years ago

I need help finding the median :)

marin [14]

Answer:

Step-by-step explanation:

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3 years ago

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