Answer:
Some flowers and some shading in it
Answer:
328 feet
Step-by-step explanation:
From a boat ont he lake, the angle of elevation to the top of a cliff is 11° 50'. If the base of the cliff is 1568 feet from the boat, how high is the cliff (to the nearest foot)
Step 1
Note that
that 11°50' is just 11 degrees and 50 minutes
60 minutes = 1 degree,
thus 50 minutes = x degree
50/60 degrees
= 0.83°
Hence: 11°50' = 11.83°.
Step 2
We solve using Trigonometric function of tan
tan theta = Opposite/Adjacent
theta = 11.83°
Adjacent = 1568 feet
Opposite = Height of the cliff = x
tan 11.83° = x/1568
Cross Multiply
x = tan 11.83 × 1568
x = 328.429195 feet
Approximately = 328 feet
The height of the cliff is 328 feet
Answer:
B. 246 in^2
Step-by-step explanation:
A = pi r^2 theta /360 if theta is in degrees
A = * pi *(16)^2 * (110/360)
A = *pi* 256 * 11/36
A = 2816/36 *pi
A = 245.74236 in ^2
Answer:
314.16
Step-by-step explanation:
Because we have the radius given to us by BC, we can simply input it into the formula to find the area of a circle, pi(r)^2.
After we insert the given radius, we have pi(10)^2.
We can simply input it into our calculator to find the answer.
Its kinda blurry and I can't read the whole question
