6-2 kites and trapezoids

2p²q³×5pq÷10p³q⁴ PLEASE SOLVE THIS EQUATION WITH WORKING. THANK YOU!

Tcecarenko [31]

Answer: p^6q^8

Step-by-step explanation:

6 0

3 years ago

Rachel surveyed her friends on the number of siblings each one had. Her results are shown in the table below.

Lynna [10]

It is A. a bar of graph

4 0

4 years ago

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22. An employee joined a company in 2017 with a starting salary of $50,000. Every year this employee receives a raise of $1000 p

Setler79 [48]

Answer:

(a) The recurrence relation for the salary is

$S_{n+1}=1.05*S_n+1000\\\\S_0=50000$

(b) The salary 25 years after 2017 will be $217044.85.

(c) $S_n=1.05^nS_0+1000*\sum_{0}^{n-1}1.05^n$

Step-by-step explanation:

We can define the next year salary $S_{n+1}$ as

$S_{n+1}=S_n+1000+0.05*S_n=1.05*S_n+1000$

wit S0=$50000

If we extend this to 2 years from 2017 (n+2), we have

$S_{n+2}=1.05*S_{n+1}+1000=1.05*(1.05*S_n+1000)+1000\\S_{n+2} =1.05^2*S_n+1.05*1000+1000\\S_{n+2}=1.05^2*S_n+1000*(1.05^1+1)$

Extending to 3 years (n+3)

$S_{n+3}=1.05*S_{n+2}+1000=1.05(1.05^2*S_n+1000*(1.05^1+1))+1000\\\\S_{n+3}=1.05^3S_n+1.05*1000*(1.05^1+1)+1000\\\\S_{n+3}=1.05^3*S_n+1000*(1.05^2+1.05^1+1)$

Extending to 4 years (n+4)

$S_{n+4}=1.05*S_{n+3}+1000=1.05*(1.05^3*S_n+1000*(1.05^2+1.05^1+1))+1000\\\\S_{n+4}=1.05^4S_n+1.05*1000*(1.05^2+1.05^1+1))+1000\\\\S_{n+4}=1.05^4S_n+1000*(1.05^3+1.05^2+1.05^1+1.05^0)$

We can now express a general equation for S_n (salary at n years from 2017)

$S_n=1.05^nS_0+1000*\sum_{0}^{n-1}1.05^n$

The salary at 25 years from 2017 (n=25) will be

$S_{25}=1.05^{25}S_0+1000*\sum_{0}^{24}1.05^i\\\\S_{25}=3.386*50000+1000*47.72=217044.85$

8 0

4 years ago

A short sale is when a house is sold _____.

Anvisha [2.4K]

a short sale is when a house is sold for less than what the mortgage is.

answer: B. for less than the mortgage owed on it

6 0

2 years ago

9.) List three things vertical and horizontal lines have in common.

12345 [234]

Answer:

Horizontal lines have a slope of zero, and run parallel to the x axis. Vertical lines have a undefined slope, and run parallel to the y axis. The equation for a horizontal line equals y=c, and the equation for a vertical line equals x=c. If a horizontal line crosses a vertical line the two lines would be perpendicular to one another.

Step-by-step explanation:

8 0

2 years ago

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