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2 years ago

Ppllllzzzzz help me plz

Mathematics

1 answer:

Sladkaya [172]2 years ago

7 0

1) a∠12 because this sign means you must be less than 12 years old as a stands for age maybe.
2) it's the 3rd one because always remember that a closed circle is for ≤ or ≥
so now you've to choose between the last two.. always remember if the sign directs right the graph is left and vice versa..Hope this helps:)

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A local gym has 2 types of cardio machines, treadmills and elliptical machines. There are 38 cardio machines in all. There are 1

Brilliant_brown [7]

Answer:

14 elliptical machines

Step-by-step explanation:

t = # of treadmills

e = # of elliptical machines

t + e = 38

t = e + 10

Substitute:

e + 10 + e = 38

2e = 28

e = 14

6 0

2 years ago

Polygon D is a scaled copy of polygon C using a scale factors of 6

Vladimir79 [104]

Answer: The area of the Polygon D is 36 times larger than the area of the Polygon C.

Step-by-step explanation:

<h3> The complete exercise is: "Polygon D is a scaled copy of Polygon C using a scale factor of 6. How many times larger is the area of Polygon D than the area Polygon C"?</h3>

In order to solve this problem it is important to analize the information provided in the exercise.

You know that the Polygon D was obtained by multiplying the lengths of the Polygon C by the scale factor of 6.

Then, you can identify that the Length scale factor used is:

$Length\ scale\ factor=k=6$

Now you have to find the Area scale factor.

Knowing that the Length scale factos is 6, you can say that the Area scale factor is:

$Area \ scale\ factor=k^2=6^2$

Finally, evaluating, you get that this is:

$Area \ scale\ factor=36$

Therefore, knowing the Area scale factor, you can determine that the area of the Polygon D is 36 times larger than the area of the Polygon C.

8 0

3 years ago

Differentiate with respect to X <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%5Cfrac%7Bcos2x%7D%7B1%20%2Bsin2x%20%7D%20

Mice21 [21]

Power and chain rule (where the power rule kicks in because $\sqrt x=x^{1/2}$ ):

$\left(\sqrt{\dfrac{\cos(2x)}{1+\sin(2x)}}\right)'=\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'$

Simplify the leading term as

$\dfrac1{2\sqrt{\frac{\cos(2x)}{1+\sin(2x)}}}=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}$

Quotient rule:

$\left(\dfrac{\cos(2x)}{1+\sin(2x)}\right)'=\dfrac{(1+\sin(2x))(\cos(2x))'-\cos(2x)(1+\sin(2x))'}{(1+\sin(2x))^2}$

Chain rule:

$(\cos(2x))'=-\sin(2x)(2x)'=-2\sin(2x)$

$(1+\sin(2x))'=\cos(2x)(2x)'=2\cos(2x)$

Put everything together and simplify:

$\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{(1+\sin(2x))(-2\sin(2x))-\cos(2x)(2\cos(2x))}{(1+\sin(2x))^2}$

$=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2\sin^2(2x)-2\cos^2(2x)}{(1+\sin(2x))^2}$

$=\dfrac{\sqrt{1+\sin(2x)}}{2\sqrt{\cos(2x)}}\dfrac{-2\sin(2x)-2}{(1+\sin(2x))^2}$

$=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac{\sin(2x)+1}{(1+\sin(2x))^2}$

$=-\dfrac{\sqrt{1+\sin(2x)}}{\sqrt{\cos(2x)}}\dfrac1{1+\sin(2x)}$

$=-\dfrac1{\sqrt{\cos(2x)}}\dfrac1{\sqrt{1+\sin(2x)}}$

$=\boxed{-\dfrac1{\sqrt{\cos(2x)(1+\sin(2x))}}}$

5 0

2 years ago

Which algebraic expression represents the phrase "two times the quantity of a number minus 12"? A. 2y - 12 B. 2(y -12) C. 2(y +

bazaltina [42]

Answer:

Step-by-step explanation:

Two times the quantity of a number minus 12.

Represent the number with the variable y.

The quantity of a number minus 12 is then: (y-12).

Two times this quantity is 2(y-12).

So the answer is 2(y-12), which is B.

5 0

2 years ago

F(x) = 2x - 1, g(x) = 3x, h(x) = x2 + 1<br> Compute the following:<br> h(f(9))

Tamiku [17]

H(2)=5-F+g(2)=(f • h)(2)=f

6 0

2 years ago