Help solve the proof! I need help with statements and reasoning

Help me please show how you got the answer

Lilit [14]

Answer:

Firstly you need to put the equation in form of. y =ax+b

Let us do it

We have

2x-2y=18

-2y=18-2x

-y=(18) /2 - (2x)/2

-y =9-x

Mutiply by - to remove it beside y

Y=-9+x

Which is y=x-9

Slope =a=1

Yintercept=b=-9

3 0

3 years ago

Solve each equation by completing the square. round to the nearest hundredth if necessary.

erastova [34]

To comlete each square, you just have to take the middle term and divide it by 2, then take its square. Add this to both sides of the equation then simplify. The middle term is the 1st degree x variable.

3. x^2+6x =16
-------------------------
(6/2)^2 = 9
x² + 6x + 9 = 16 + 9
(x + 3)² = 25

4. x^2-10x =11
------------------------
(-10/2)² = 25
x² - 10x + 25 = 11 + 25
(x -5)² = 36

5. x^2-9x =0
--------------
(-9/2)² = 81/4
x² - 9x + 81/4 = 81/4
(x - 9/2)² = 81/4

6. x^2+16x =15
---------------
(16/2)² = 64
x² + 16x +64 = 15 + 64
(x + 8)² = 79

7. 3x^2+18x-81=0
----------------
x² + 6x = 27
(6/2)² = 9
x² + 6x + 9 = 27 + 9
(x + 3)² = 36

A polynomial with a general equation of ax² + bx + c = 0 has a root determined using this formula:

$x= \frac{-b \ +/- \ \sqrt{ b^{2}-4ac } }{2a}$

Just substitute the coefficients to the formula to find the roots

8. 1.09, -1.84
9. 3, 1/2
10. No real roots
11. 1.12, -3.12

4 0

3 years ago

Read 2 more answers

HELP HELP HELP!!! i need help with math pls help me.

12345 [234]

Answer:

I dont even know this myself o-o

Step-by-step explanation:

:D

5 0

3 years ago

One pipe can empty a tank 5 times faster than another pipe can fill the tank. Starting with a full tank, if both pipes are turne

xxTIMURxx [149]

Answer:

40 hours

Step-by-step explanation:

Let's say that the slower pipe can fill x amount of the tank in one hour. It adds x amount to the tank every hour. Therefore, we can say, for the slower pipe,

1 hour = x amount

Then, the faster pipe empties the tank 5 times faster than the slower pipe fills it, so it removes 5 times the amount that the smaller pipe puts in, so for the faster pipe,

1 hour = -5x amount (negative to symbolize removing).

For the problem at hand, the tank starts at full, or 100%=1. It ends empty, or at 0% = 0. After 10 hours, if we only account for the slower pipe, we add x amount to the tank every hour, so we add 10 times that total, resulting in

1 + 10 * x as the ending result if we don't include the faster pipe. Then, the faster pipe removes 5x every hour, so in 10 hours, it removes 50x, so we have

1+10 * x - 50 * x as the final amount of stuff in the tank, which is equal to 0. Therefore, we have

1 + 10 * x - 50 * x = 0

1 - 40 * x = 0

add 40*x to both sides to isolate the x and its coefficient

1 = 40 * x

divide both sides by 40 to isolate x

x= 0.025

Therefore, the slower pipe adds 0.025, or 1/40 = 2.5% to the tank every hour. We want to figure out how long it would take for the slower pipe to fill up an empty tank, or turn it from 0% to 100% full.

Because the slower pipe adds 2.5% of the tank every hour, we can say that over y hours, it fills up

2.5% * y amount of the tank. We want to figure out how many hours it would take to make it 100% (we need to add 100% of the tank in the problem), so we can say

2.5% * y = 100%

divide both sides by 2.5% to isolate y

100%/2.5% = y = 40

5 0

3 years ago

A circle has been split into 8 sectors each of which can be colored as 4 different colors, and no consecutive sectors are colore

Eva8 [605]

Answer:

5832 ways

Step-by-step explanation:

Since the circle has 8 sectors and there is 4 colour,

Assuming the sectors are numbered 1 to 8,

Sector 1 : can be coloured with any of the 4 colour in 4 ways

Sector 2 can be coloured with any of the remaining 3 colours in 3 ways

Sector 3 in 3 ways without using the colour in sector 2

Sector 4 in 3 ways without using the colour in sector 3

Sector 5 in 3 ways without using the colour in sector 4

Sector 6 in 3 ways without using the colour in sector 5

Sector 7 in 3 ways without using the colour in sector 6

Sector 8 in 2 ways without using the colours in sector 1 and 7

Number of ways of colouring = 4*3*3*3*3*3*3*2 = 5832 ways

3 0

3 years ago

Help solve the proof! I need help with statements and reasoning ​

Help solve the proof! I need help with statements and reasoning