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Zarrin [17]
3 years ago
14

If (x + 2 ) is a factor of x3 − 6x2 + kx + 10, k =

Mathematics
2 answers:
BartSMP [9]3 years ago
8 0
If a binomial x-a is a factor of a polynomial p(x), then p(a)=0.

x+2 is a factor of p(x)=x³-6x²+kx+10, so p(-2)=0.

p(-2)=0 \\
(-2)^3 - 6 \times (-2)^2 + k \times (-2) + 10=0 \\
-8-6 \times 4-2k+10=0 \\
-8-24-2k+10=0 \\
-2k-22=0 \\
-2k=22 \\
k=\frac{22}{-2} \\
\boxed{k=-11}
Gwar [14]3 years ago
4 0

Answer:

-11

Step-by-step explanation:

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sergey [27]
31/3: 2/3= 5
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3 years ago
What is the solution to the system of linear equations?
AlexFokin [52]
X=8-y

2(8-y)=10
16-2y=10
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Determine the y intercept of the graph y-7 =3(x+5) rearrange in slope intercept form
MatroZZZ [7]

Answer:

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8 0
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Read 2 more answers
What the answers for those questions
Minchanka [31]

The answers are

11. c) 7x² +5x +8 remainder 7.

12. d) 6x² -6x +3 remainder 2x.

Step-by-step explanation:

Step 1; By dividing 7x³ -2x² +3x -1 with x -1 we get the following calculations. We multiply 7x² with x-1 and get 7x³ - 7x². We subtract this from 7x³ -2x² and get 5x². Now we add this with the 3x in 7x³ -2x² +3x -1. We get 5x² +3x. We multiply x -1 with 5x and get 5x² -5x and subtract it from 5x² +3x and get 8x. We multiply the x -1 with 8 and get 8x -8. We subtract this from 8x -1 and get a remainder of 7. So the quotient is 7x² +5x +8 with a remainder of 7.

Step 2; By dividing 6x^{4} +0x³ -3x² +5x with x² +x we get the following calculations. We multiply 6x² with x² +x and get 6x^{4} +6x³. We subtract this from 6x^{4} +0x³ and get -6x³. Now we add this with the -3x² in 6x^{4} +0x³ -3x² +5x. We get -6x³ -3x². We multiply x² +x with -6x and get -6x³ -6x² and subtract it from -6x³ -3x² and get 3x². We multiply the x² +x with 3 and get 3x² +3x. We subtract this from 3x² +5x and get a remainder of 2x. So the quotient is 6x² -6x +3 with a remainder of 2x.

4 0
3 years ago
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