The volume of five volleyballs is 26310.15 cubic cm if the volleyball has a surface area of 1465 square cm.
<h3>What is a sphere?</h3>
It is defined as three-dimensional geometry when half-circle two-dimensional geometry is revolved around the diameter of the sphere that will form.
We know the surface area of the sphere is given by:
SA = 4πr²
1465 = 4πr²
r = 10.79 cm
Volume of the sphere = 4πr³/3
V = 4π(10.79)³/3
V = 5262.03 cubic cm
Volume of five volleyballs = 5×5262.03 = 26310.15 cubic cm
Thus, the volume of five volleyballs is 26310.15 cubic cm if the volleyball has a surface area of 1465 square cm.
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I did a few, to show you how.
Slide 1:
A) class A; range of 7
B) class a; 5.5
C) class b; 6.7 appx
D) class a
These are how to find each one:
Mean: add all the numbers and divide by the number of numbers. Ex. 1+2+3= 6/3=2
Median: middle of the numbers
Range: take the smallest value away from the largest value
IQR: find the median; find the range of the numbers above and below the median. Take the range of those two numbers that is the IQR
MAD: find the mean; take absolute value of numbers and subtract mean (|x|-mean); find sum of absolute value and difference; divide by the number of numbers.
Answer:
The answer is LB= 8 feet
Step-by-step explanation:
This trinomial is in a special form that can
be factored as the product of two binomials.
<h2>x² - 10x + 25</h2><h2 />
The first term in each binomial will be a factor of the x² term.
Since x² is just x · x, we use those as our first factors.
To factor this trinomial, we need factors of our constant that
add to the coefficient of the middle term in our trinomial.
So we're looking for factors of 25 that add to -10.
When your constant is positive and your middle term is negative,
you are going to use the negative factors of your constant term.
So the two numbers hat multiply to gives
us 25 and add to -10 are -5 and -5.
So our answer is (x - 5)(x - 5).
Answer:
A) There are no Counts
B) I'll count the number of each type of nut.
Step-by-step explanation:
A) Yes, the Chi-square is not an appropriate method because the question gave us the weight of the nuts in grams and these are not counts. Whereas, the chi-square goodness-of-fit test requires that the data values are counts.
B) What i will do instead is that i will count the number of each type of nut and assume that the given percentages are also relevant for each type of nut.
