Answer:
This is really hard. I tried doing this problem but of was a real pain. I honestly can't help. I tried. sorry mate.
Answer:
<em>#include <iostream></em>
<em>using namespace std;</em>
<em>int main()</em>
<em>{</em>
<em> int myNewAge;</em>
<em> int myCurrentAge = 29;</em>
<em> int currentYear = 2020;</em>
<em> </em>
<em>myNewAge = myCurrentAge+(2050-currentYear);</em>
<em />
<em>cout<<"My Current Age is "<<myCurrentAge<<". I will be "<<myNewAge<<" in 2050"<<endl;</em>
<em> return 0;</em>
<em>}</em>
Explanation:
The program is written in C++ language as required. firstly, we declare the three variables:
<em> </em><em>int myNewAge;</em>
<em> int myCurrentAge = 29;</em>
<em> int currentYear = 2020;</em>
Then we calculate the new age as: <em>myNewAge = myCurrentAge+(2050-currentYear);</em>
Using multiple cout operators (<em> </em><<) we display the output nicely as required by the question with this statement
<em>cout<<"My Current Age is "<<myCurrentAge<<". I will be "<<myNewAge<<" in 2050"<<endl;</em>
Answer:
B.4.75
Explanation:
Buffer solutions are the solutions which can resist the change in the pH up to some extent. They are the solutions of either weak acid and conjugate base of it or weak base and conjugate acid of it.
The pH of a buffer solution can be measured by the equation known as Henderson–Hasselbalch equation.
pH=pKa+log[base]/[acid]
A good buffer that buffer which has its acid's pKa within one pH unit of desired experimental conditions.
Thus, desired pH = 5.3
Preferable pKa = 4.3 - 6.3
<u>Answer - B. 4.75</u>
True. Most basic programs follow this structure.
Answer:
B)
Explanation:
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