TheThe smallest diameter of wrapper that will fit the candy bar is 5cm.
<h3>Smallest diameter</h3>
Given:
AD = DC
AC = AD + DC
Segment AD = 2.5cm
Hence:
AC = AD + AD (AD = DC)
AC = 2AD
Where:
AD=2.5
So,
AC = 2(2.5cm)
AC = 5cm
Therefore the smallest diameter of wrapper that will fit the candy bar is 5cm.
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Answer:
- h = 0 when the ball hits the ground
- about 3.464 seconds
Step-by-step explanation:
The formula gives h = 192 when t=0, so we assume that h represents the height above the ground. The ball will have a height of 0 when it hits the ground.
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Using that in the equation, we can solve for t.
0 = 192 -16t^2
0 = 12 -t^2 . . . . . . divide by 16
t^2 = 12 . . . . . . . . add t^2
t = √12 = 2√3 ≈ 3.464 . . . . take the square root
It will take 2√3 seconds, about 3.464 seconds, for the ball to hit the ground.
A would equal 1.1148990985734988
Answer:
5
Step-by-step explanation:
The range is the largest minus the smallest; 6-1= 5
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Solution:
we are given that
A school director Must randomly select 6 teachers to participate in a training session there are 30 teachers at the schoo. The order of selection does not matter.
As we know
6 teacheras can be selected out of 30 teacher in 
ways.
Hence the required number of ways is 593775.
