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Lera25 [3.4K]
3 years ago
12

Rewrite the volume for Rectangular Solid for w

Mathematics
1 answer:
icang [17]3 years ago
8 0
I don’t see the original volume
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36.00x0.07 show explanation
makkiz [27]

Answer: 2.52

Step-by-step explanation: 36.00x0.07

36.00 is the same as 36

so, 36x0.07=2.52

5 0
2 years ago
When a dice is rolled find the probability of getting a number less than or equal to 6
Dahasolnce [82]

Answer:

100% probability right?

Step-by-step explanation:

a dice only has 6 sides

7 0
2 years ago
Which represents the solution set of an any quality 5X-9 greater than 21
Svet_ta [14]

Answer:

The last one

Step-by-step explanation:

5x<30

x<6

Because when you divide by pos+ number

the symbol cannot change.

6 0
3 years ago
Do I need to put parentheses in this? Why it why not?
Oksana_A [137]

Answer:

Parentheses can change the result of the answer. If you want to add 4 and 0.95 first, then multiply that number by 3, then you need parentheses.

Step-by-step explanation:

When you are given the question 3 X 4 + 0.95, it has to types of operations. <u>People solve using the order PEDMAS</u>:

Parentheses,

Exponents,

Division and Multiplication,

Addition and Subtraction.

Since there are <u>no parentheses</u> or exponents, the solver will do multiplication first, then addition.

3 X 4 + 0.95     Multiply first

= 12 + 0.95       Now add

= 12.95         Answer without parentheses

If you add <u>parentheses around 4 + 0.95</u>, the answer would change. According to PEDMAS, the parentheses must be solved before anything else.

3 X (4 + 0.95)       Add inside parentheses

= 3 X (4.95)       Now multiply

= 14.85           Answer with parentheses

If you added <u>parentheses around 3 X 4</u>, the answer would not change, because you still multiply first.

(3 X 4) + 0.95      Solving parentheses first

= 12 + 0.95       Add

= 12.95          Answer same as original

3 0
3 years ago
Find the equation in general form of the circle with center at the origin and radius equal 6.
____ [38]
\bf \textit{equation of a circle}\\\\ &#10;(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2&#10;\qquad &#10;\begin{array}{lllll}&#10;center\ (&{{ h}},&{{ k}})\qquad &#10;radius=&{{ r}}\\&#10;&0&0&6&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;(x-0)^2+(y-0)^2=6^2\implies x^2+y^2=36
3 0
3 years ago
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