It is a bit tedious to write 6 equations, but it is a straightforward process to substitute the given point values into the form provided.
For segment ab. (x1, y1) = (1, 1); (x2, y2) = (3, 4).
... x = 1 + t(3-1)
... y = 1 + t(4-1)
ab = {x=1+2t, y=1+3t}
For segment bc. (x1, y1) = (3, 4); (x2, y2) = (1, 7).
... x = 3 + t(1-3)
... y = 4 + t(7-4)
bc = {x=3-2t, y=4+3t}
For segment ca. (x1, y1) = (1, 7); (x2, y2) = (1, 1).
... x = 1 + t(1-1)
... y = 7 + t(1-7)
ca = {x=1, y=7-6t}
<em>*To solve for a specified variable, you need to isolate that variable onto one side.</em>
<h3>11.</h3>
Firstly, subtract 5r on both sides: 
Lastly, divide both sides by 2 and <u>your answer will be 
</u>
<h3>12.</h3>
First, subtract z on both sides of the equation: 
Next, divide both sides by y and <u>your answer will be 
</u>
<h3>13.</h3>
Firstly, multiply both sides by b: 
Next, divide both sides by c and <u>your answer will be 
</u>
The correct classification for the polygon would be a concave hexagon.
Answer:
C. It increases by a factor of 110
Step-by-step explanation:
For Plato
