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3 years ago

Which equation is in standard form?

Mathematics

1 answer:

DedPeter [7]3 years ago

5 0

The answer is "A" because you need your equation to be like:
Ax + By = C

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I have tried solving and constantly find myself stuck someone please help my test is tomorrow!!!

Veseljchak [2.6K]

Answer:

Is The Test On An Ipad? Or Computer?

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3 years ago

6= 4x+9y solve for y

rosijanka [135]

Let's solve for y.6=4x+9yStep 1: Flip the equation.4x+9y=6Step 2: Add -4x to both sides.4x+9y+−4x=6+−4x9y=−4x+6Step 3: Divide both sides by 9.9y9=−4x+69y=−49x+23

6 0

3 years ago

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How many 1/3 are in 7/3?

lisabon 2012 [21]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

There are 10 computers and 5 students. How many ways are there for the students to sit at the computers if no computer has more

mestny [16]

Answer:

30,240 ways

Step-by-step explanation:

This question is bothered on permutation. Permutation has to do with arrangement.

If there are 10 computers and 5 students, the number of ways students will sit at the computers if no computer has more than one student can be expressed as;

10P5 = 10!/(10-5)!

10P5 = 10!/(5)!

10P5 = 10*9*8*7*6*5!/5!

10P5 = 10*9*8*7*6

10P5 = 30,240

Hence the number of ways is 30,240 ways

6 0

3 years ago

walnut grower estimates from past records that if 20 trees are planted per acre, then each tree will average 60 pounds of nuts p

laila [671]

Answer:

5 trees should be planted to maximize the yield per acre,

The maximum yield would be 1250

Step-by-step explanation:

Given,

The original number of trees per acre = 20,

Average pounds of nuts by a tree = 60,

Let x be the times of increment in number of trees,

So, the new number of trees planted per acre = 20 + x

∵ for each additional tree planted per acre, the average yield per tree drops 2 pounds,

So, the new number of pounds of nut = (60 - 2x)

Thus, the total yield per acre,

$Y(x) = (20+x)(60-2x)$

Differentiating with respect to t ( time ),

$Y'(x) = (20+x)(-2) + 60 - 2x = -40 - 2x + 60 - 2x = 20 - 4x$

Again differentiating with respect to t,

$Y''(x) = -4$

For maxima or minima,

$Y'(x) = 0$

⇒ 20 - 4x = 0

⇒ 20 = 4x

⇒ x = 5,

For x = 5, Y''(x) = negative,

Hence, Y(x) is maximum for x = 5,

And, maximum value of Y(x) = (20+5)(60 - 10) = 25(50) = 1250,

i.e. 5 trees should be planted to maximize the yield per acre,

and the maximum yield would be 1250 pounds

4 0

3 years ago