X^3 = 216
by taking cubic root for both sides
![\sqrt[3]{x^3} = \sqrt[3]{216}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20%20%5Csqrt%5B3%5D%7B216%7D%20)
x = 6
Answer:
what is the question?
Step-by-step explanation:
Answer:
p=30 q=150
Step-by-step explanation:
Given two points A(x₁,y₁) and B(x₂,y₂) the distance betwen these points will be:
dist(A,B)=√[(x₂-x₁)²+(y₂-y₁)²].
We have these points: A(0,0) and B(6,3); its distance will be:
dist(A,B)=√[(6-0)²+(3-0)²]
=√(6²+3²)
=√(36+9)
=√45 ≈ 6.71
Answer: D. 6.71 units.
N - 2 = 10n + 4/2
-2 = 9n + 4/2
-4/4 = 9n
-1 = 9n
-9 = n
N is -9.
If this answer is right please leave a thanks and a rating. :)