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Sedbober [7]
3 years ago
14

What’s the answer for 3n-6=33 I have to solve for n

Mathematics
2 answers:
dezoksy [38]3 years ago
7 0

Answer:

n=13

Step-by-step explanation:

3n-6=33

Add 6 to both sides

3n=39

Divide both sides by 3

n=13

4vir4ik [10]3 years ago
3 0

Answer:

n= 13

Step-by-step explanation:

Hope this helps you out ;)

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Fluffy, Spot and Skampy have a combined age in dog years of 91. Spot is 14 years younger than Fluffy. Skampy is 6 years older th
WITCHER [35]

Answer: fluffy = 33yrs

Spot = 19 yrs

Skampy = 39 yrs

Step-by-step explanation:

Let fluffy = x

Spot = y

Skampy =z

x + y + z = 91 -------1

x -14 =y ------2

z = x + 6 --------3

Put eqn 2 and 3 in eqn 1

x + x - 14 + x + 6 = 91

3x = 99

x = 33

y = 33-14= 19

z = 33+6 = 39

8 0
3 years ago
Solve the equation <br> -13/4 -x= 1/2x -1
ale4655 [162]

Answer:

x = 2 or 1/4

Step-by-step explanation:

-13/4 -x= 1/2x -1

Collect like terms

-13/4+1=1/2x+x

Using LCM

(-13+4)/4=(1+2x²)/2x

9/4=(1+2x²)/2x

Cross multiply

9(2x)=4(1+2x²)

18x=4+8x²

Turn into quadratic and solve

8x²-18x+4

Using formulae method

-b±(√b²-4ac)/2a

Where a=8, b= -18 and c=4

(-(-18)±(√(-18)²-4(8)(4))/2(8)

(18±(√324-128))/16

(18±√196)/16

(18±14)/16

(18+14)/16 or (18-14)/16

32/16 or 4/16

2 or 1/4

4 0
3 years ago
Read 2 more answers
I need help with a problem with solving by square roots in quadratic equation.
Readme [11.4K]

To solve for x, first, we add 3 to the given equation:

\begin{gathered} 2(x+5)^2-3+3=44+3, \\ 2(x+5)^2=47. \end{gathered}

Dividing by 2, we get:

(x+5)^2=\frac{47}{2}.

Therefore:

x+5=\pm\sqrt{\frac{47}{2}}.

Finally, subtracting 5 we get:

x=\pm\sqrt{\frac{47}{2}}-5.

Answer:

x=\operatorname{\pm}\sqrt{\frac{47}{2}}-5.

4 0
1 year ago
GEOMETRY HELP, 11th GRADE
Trava [24]

Answer:

True

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Suppose a company needs temporary passwords for the trial of a new payroll software. Each password will have one digit followed
Alekssandra [29.7K]

Answer:  The required number of passwords that can be created is 175760.

Step-by-step explanation:  Given that a company needs temporary passwords for the trial of a new payroll software.

Each password will have one digit followed by three letters and the letters can be repeated.

We are to find the number of passwords that can be created using this format.

For the one digit in the password, we have 10 options, 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.

Since there are 26 letters in English alphabet and letters can be repeated, so the number of options for 3 letters is

26 × 26 × 26 = 17576.

Therefore, the total number of ways in which passwords can be created using the given format is

n=9\times17576=175760.

Thus, the required number of passwords that can be created is 175760.

3 0
3 years ago
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