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Oduvanchick [21]

3 years ago

5

Packages of cookies must weigh 13.75 ounces when rounded to the nearest hundredth, or a sorting machine removes them from being

sold. Which cookie package weights will round to 13.75 ounces? Choose all that are correct. a. 13.749 ounces b. 13.739 ounces c. 13.752 ounces d. 13.758 ounces e. 13.750 ounces f. 13.705 ounces

1 answer:

denis23 [38]3 years ago

6 0

Answer:

13.705 ounces is the Answer

Step-by-step explanation:

ounces? Choose all that are correct. a. 13.749 ounces b. 13.739 ounces c. 13.752 ounces d. 13.758 ounces e. 13.750 ounces f. 13.705 ounces

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There are 10 history books in a bookcase. When

Salsk061 [2.6K]

Answer:

D) 140

Step-by-step explanation:

140% of 10 is 14 and 14 added to ten is 24

8 0

3 years ago

The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi

storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

$V = \frac{1}{3}\pi r^{2}h$

Differentiate the equation with respect to time t, such that

$\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)$

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)$

To differentiate the product,

Let r² = u, so that

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)$

Then, using product rule

$\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]$

Since $u = r^{2}$

Then, $\frac{du}{dr} = 2r$

Using the Chain's rule

$\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}$

∴ $\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]$

Then,

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

Now,

From the question

$\frac{dr}{dt} = 7 m/min$

$\frac{dV}{dt} = 236 m^{3}/min$

At the instant when $r = 99 m$

and $V = 180 m^{3}$

We will determine the value of h, using

$V = \frac{1}{3}\pi r^{2}h$

$180 = \frac{1}{3}\pi (99)^{2}h$

$180 \times 3 = 9801\pi h$

$h =\frac{540}{9801\pi }$

$h =\frac{20}{363\pi }$

Now, Putting the parameters into the equation

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

$236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]$

$236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]$

$708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}$

$708 = 30790.75 \frac{dh}{dt} + 76.36$

$708 - 76.36 = 30790.75\frac{dh}{dt}$

$631.64 = 30790.75\frac{dh}{dt}$

$\frac{dh}{dt}= \frac{631.64}{30790.75}$

$\frac{dh}{dt} = 0.021 m/min$

Hence, the rate of change of the height is 0.021 meters per minute.

3 0

3 years ago

Someone pls help me :)

klasskru [66]

1.

25%

.3 + .2 + .15 + .1 = .75

1.00 - .75 = .25

2.

120 students

There are 400 total students

.3 * 400 = 120

4.

tennis-

.1 * 400 = 40 students prefer tennis

football-

.25 * 400 = 100 students prefer football

140 students like football/tennis

5.

400 students

There are four quarters in a whole

.25% = 100

100 * 4 = 400

4 0

3 years ago

What is the product?

Alona [7]

Answer:

$\boxed{- 12 {s}^{2} + 11st - 2 {t}^{2} }$

Step-by-step explanation:

$= > ( - 3s + 2t)(4s - t) \\ \\ = > - 3s(4s - t) + 2t(4s - t) \\ \\ = > ( ( - 3s) \times 4s )- (( - 3s) \times t) + (2t \times 4s) - (2t \times t) \\ \\ = > - 12 {s}^{2} - ( - 3st) + 8st - 2 {t}^{2} \\ \\ = > -12 {s}^{2} + 3st + 8st - 2 {t}^{2} \\ \\ = > - 12 {s}^{2} + 11st - 2 {t}^{2}$

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3 years ago

The segments shown below could form a triangle.<br> help please :)

leonid [27]

That’s false because two lines are to short so it’s false

8 0

3 years ago

Read 2 more answers