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Lunna [17]
2 years ago
15

A pool drains 5000 gallons of water over the course of 5 hours. How many gallons of water, on average, does the pool drain each

hour?
A. -5000 gallons per hour
B. -1000 gallons per hour
C. -100 gallons per hour
D. 1000 gallons per hour
Mathematics
2 answers:
Zolol [24]2 years ago
7 0

Answer: If it drained 5000 gallons and there were 5 hours, then 5000 divided by 5 is 1 so that would be answer D.

Hoped this helped!

Dmitry [639]2 years ago
6 0

Answer:

D. 1000 gallons per hour

Step-by-step explanation:

5000 / 5 = 1000

You might be interested in
Length of the bases and h is the height, to answer the question. How many square feet of grass
Aleonysh [2.5K]

Answer:

There are 7,725 square feet of grass on the trapezoidal field

Step-by-step explanation:

Here in this question, we are interested in calculating the square feet of grass present on the trapezoidal field.

What this question is actually asking us is to calculate the area of the trapezoid-shaped grass field.

To calculate this area, what we need to do

simply is to use the formula for the area of a trapezoid.

Mathematically, the area of a trapezoid can be calculated using the formula;

Area of trapezoid = 1/2 * (a + b) * h

where a and b refers to the length of the parallel lengths of the trapezoid and h refers to the height of the trapezoid.

From the question;

a, b = 81ft and 125 ft

h = 75 ft

Substituting these values, we have :

Area = 1/2 * (81 + 125) * 75

Area = 1/2 * 206 * 75 = 83 * 75 = 7,725 ft^2

6 0
2 years ago
Which expression is it equivalent to?
horrorfan [7]
Option A) Is the answer. \boxed{\mathbf{\dfrac{3f^3}{g^2}}}

For this question; You are needed to expose yourselves to popular usages of radical rules. In this we distribute the squares as one-and-a-half fractions as the squares eliminate the square roots. So, as per the use of fraction conversion from roots. It becomes relatively easy to solve and finish the whole process more quicker than everyone else. More easier to remember.

Starting this with the equation editor interpreter for mathematical expressions, LaTeX. Use of different radical rules will be mentioned in between the steps.

Radical equation provided in this query.

\mathbf{\sqrt{\dfrac{900f^6}{100g^4}}}

Divide the numbered values of 900 and 100 by cancelling the zeroes to get "9" as the final product in the next step.

\mathbf{\sqrt{\dfrac{9f^6}{g^4}}}

Imply and demonstrate the rule of radicals. In this context we will use the radical rule for fractions in which a fraction with a denominator of variable "a" representing a number or a variable, and the denominator of variable "b" representing a number or a variable are square rooted by a value of "n" where it can be a number, variable, etc. Here, the radical of "n" is distributed into the denominator as well as the numerator. Presuming the value of variable "a" and "b" to be greater than or equal to the value of zero. So, by mathematical expression it becomes:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{\dfrac{a}{b}} = \dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}, \: \: a \geq 0 \: \: \: b \geq 0}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{\sqrt{g^4}}}

Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{g^4} = g^{\frac{4}{2}}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{g^2}}

Exhibit the radical rule for two given variables in this current step to separate the variable values into two new squares of variables "a" and "b" with a radical value of "n". Variables "a" and "b" being greater than or equal to zero.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}, \: \: a \geq 0 \: \: \: b \geq 0}}

So, the square roots are separated into root of 9 and a root of variable of "f" raised to the value of "6".

\mathbf{\therefore \quad \dfrac{\sqrt{9} \sqrt{f^6}}{g^2}}

Just factor out the value of "3" as 3 × 3 and join them to a raised exponent as they are having are similar Base of "3", hence, powered to a value of "2".

\mathbf{\therefore \quad \dfrac{\sqrt{3^2} \sqrt{f^6}}{g^2}}

The radical value of square root is similar to that of the exponent variable term inside the rooted enclosement. That is, similar exponential values. We apply the following radical rule for these cases for a radical value of variable "n" and an exponential value of "n" with a variable that is powered to it.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^n} = a^{\frac{n}{n}} = a}}

\mathbf{\therefore \quad \dfrac{3 \sqrt{f^6}}{g^2}}

Again, Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{f^6} = f^{\frac{6}{2}} = f^3}

\boxed{\mathbf{\underline{\therefore \quad Required \: \: Answer: \dfrac{3f^3}{g^2}}}}

Hope it helps.
8 0
3 years ago
Can someone please help me with #12?
Genrish500 [490]

4x+12=90

4x=90-12

4x=8

x=8/4

x=2

5 0
2 years ago
Can someone pls help me with this?
lara [203]

Answer:

14 is A

15 is B

Step-by-step explanation:

14 . the answer is a because first off the slope is negative so we can immediately eliminate B and D second of all the slope is 1/2 so we can eliminate D and get that the answer has to be a

15. answer is B for this one because first of all the slope is negative so we can immediately eliminate A and c and second of all the y-intercept would be 120 because 90 is what x=1 so we would have to add 30 to get what y would equal when x=0 if that makes sense

5 0
2 years ago
Explain how you know that x^2-8x+20 is always positive. <br> Please help.
IRISSAK [1]

Answer:

if you rearrange to complete the square, you get (x^2-4)^2 +4

and seeing as anything squared will always be positive or zero, the lowest possible value for (x^2-4)^2 is 0, when x = 4

and 0 + 4 = 4, which is greater than 0, so positive

Step-by-step explanation:

4 0
2 years ago
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