Answer:
translation
Step-by-step explanation:
because a reflection across the x-axis is not right, and neither is across the y-axis. The triangle was also not rotated 90 degrees. It was translated 8 units to the right and 4 units up.
Answer:
37 cents
Step-by-step explanation:
To calculate the area of a triangle you need the base & the altitude to this base:
Area triangle = 1/2(B x H)
Let's draw the altitude A intersecting BC in H. WE get now a right triangle AHB. We know AG = 9.2 we know the angle B =27°, so we can find the altitude AH through trigonometry :
sin(B) = opposite side over hypotenuse
sin(27°) = AH/AB==> sin(27°) =0.454 ==0.454= AH/9.2==>AH =0.454*9.2
AH = 4.177
Area triangle ABC = (1/2) * 11.9 * 4.177= 24.85
(L=17m and W=20m) and (L=40m and W=8.5m) are the possible dimensions (length and width) of the field given that the three sided fence has a length of 57m the area of the land is 340 square meters. This can be obtained by forming quadratic equation for the data.
<h3>Calculate the set of possible dimensions (length and width) of the field:</h3>
Let length be L and width be W.
Given that,
three sided fence has a length of 57m,
⇒ 2W + L = 57 m ⇒ L = 57 - 2W
the area of the land is 340 square meters
length × width = 340 ⇒ L × W = 340
(57 - 2W)W = 340
57W - 2W² = 340
2W² - 57W + 340 = 0
Solve for W using quadratic formula,
a = 2, b = -57, c = 340
W = (-b±√b²-4ac)/2a
= (57±√3249-2720)/4
= (57±√529)/4
= (57±23)/4
W = 20 m and W = 8.5 m
For W=20, L=57-2(20) = 17
For W=8.5, L=57-2(8.5) = 40
Hence (L=17m and W=20m) and (L=40m and W=8.5m) are the possible dimensions (length and width) of the field given that the three sided fence has a length of 57m the area of the land is 340 square meters.
Learn more about quadratic equations:
brainly.com/question/5975436
#SPJ1
