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Stels [109]
2 years ago
11

Anyone know how to solve this?

Mathematics
1 answer:
AnnyKZ [126]2 years ago
6 0

Answer:

b = 22

Step-by-step explanation:

Here b represents the length of the hypotenuse, and 11 is the length of the side opposite the 30 degree angle.  We want to find the value of b.  We use the sine function here because we have the angle measurement (b), the angle 30 degrees and the "opposite side" 11:

sin 30 degrees = (1/2) = 11/b, which, if inverted, is 2 = b/11, or b = 22

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4x + y< 2
bulgar [2K]

The two inequalities can be rewritten as

\begin{cases}y-2\end{cases}

The solution is composed by every point below the graph of the line y=-4x+2, and above the horizontal line y=-2

To draw the line y=-4x+2 we can build a little table (only 2 points are required):

\begin{array}{c|c}x&y\\0&2\\1&-2\end{array}

So, if you draw the points (0,2) and (1, -2) and connect them, you'll have your line.

To draw the line y=-2, simply pick any point with y coordinate -2, for example (0, -2), and draw a horizontal line.

Choose the above/below areas as specified above to solve the system.

5 0
3 years ago
0f the 64 students in grade five, 3/8 of them either walk or ride a bike to school. The rest take a bus. How many fifth graders
UkoKoshka [18]
40 fifth graders take a bus to school. 8x8= 64 so they have you a good fraction to start with to find out how many kids are walking or taking their bike (3/8) all you have to do is multiply 3 and 8 which equals 24 to find the fraction of the amount of kids who take the bus you subtract 3 from 8 which gives 5/8 and to get the answer you multiply 5 and 8 which is 40.
3 0
3 years ago
Is y=150x proportional?
daser333 [38]

Answer:

yes

Step-by-step explanation:

A proportional equation is of the form

y = kx where k is the constant of proportionality

y = 150x is proportional

5 0
3 years ago
Read 2 more answers
Can u please help me with question c
densk [106]

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the y-axis

a point (x, y ) → (- x, y )

Hence

A'(-5, - 3 ) → A''(5, - 3 )

B'(4, 4 ) → B''(- 4, 4 )

C'(4, 2 ) → C''(- 4, 2 )

D'(- 2, - 1 ) → D''(2, - 1 )


8 0
3 years ago
How can I solve these problems​
Anuta_ua [19.1K]
Here’s the first few and you can do the rest with the same principles. If you need more help with the last ones then let me know

4 0
3 years ago
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