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Mars2501 [29]
2 years ago
5

A van travels 300 miles on 15 gallons of gas. Find how many gallons the van needs to travel 360 miles

Mathematics
1 answer:
ANTONII [103]2 years ago
7 0

Answer:  The Van needs 18 gallons of gas to travel 360 miles.

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There are 30 students in a class that took a test. The average grade of 10 students was 80. The other 20 students average was 89
Vsevolod [243]
10 students averaged 80, so the sum of their scores was (10 x 80) = 800

20 students averaged 89, so the sum of their scores was (20 x 89) = 1,780

All together, the sum of all 30 scores was (800 + 1,780) = 2,580

30 students totaled 2,580, so their average was  (2,580 / 30)  = <em> 86</em> .
6 0
3 years ago
HELP!!! if a hospital patient is given 50 milligrams of medicine, which leaves the bloodstream at 10% per hour, how many milligr
kipiarov [429]

Answer:

I also got 27.44 mg.

Step-by-step explanation:

Use the function given to you:

A(t)=le^rt

l: Initial Amount (50)

r: Rate (-.1) (Negative because the medicine is exiting the bloodstream at 10% per hour

t: 6 (the specific time value you are evaluating the function at.

A(6)=50e^-.1(6)=27.44

8 0
3 years ago
Use your knowledge of similar triangles to solve for x
MrMuchimi

9514 1404 393

Answer:

  x = 10 2/3

Step-by-step explanation:

The ratios of corresponding sides are the same, so we have ...

  x/8 = 8/6

  x = 8·(8/6) = 64/6

  x = 10 2/3

6 0
3 years ago
What is 6/8 * 4/6?<br> Please answer this!!!
irina1246 [14]
6*4=24
8*6=48
24/48=4/8=1/2
I hope this helps;)
3 0
3 years ago
Vertex form is f(x)=a(x-p)^2 +q. How do i determine a?
slamgirl [31]
Y1 is the simplest parabola.  Its vertex is at (0,0) and it passes thru (2,4).  This is enough info to conclude that y1 = x^2.

y4, the lower red graph, is a bit more of a challenge.  We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).

Let's try this:  assume that the general equation for a parabola is 
y-k = a(x-h)^2, where (h,k) is the vertex.  Subst. the known values,

-3-(-4) = a(2-0)^2.  Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.

The equation of parabola y4 is   y+4 = (1/4)x^2

Or you could elim. the fraction and write the eqn as 4y+16=x^2, or

4y = x^2-16, or    y = (1/4)x - 4.  Take your pick!  Hope this helps you find "a" for the other parabolas.


8 0
3 years ago
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