Answer:
7 mins
Step-by-step explanation:
Current speed of Joes Car = 65.5 mph
We have to find the time interval for which the car exceeded the speed limit of 55 mph.
While, we are given that the speed of the car was constantly increasing, hence the speed over all increased from the limit of 55 mph = 65.50-55.00 = 10.50 mph
We are also given that Joes car was increasing speed at a constant rate of 1.50 mph for every passing minute. Hence
1.50 mph is increased in 1 minute
1 mph will be increase in 
minutes
Hence
10.50 mph will be increased in 
minutes
Hence joes car was exceeding the limit of 55 mph for 7 minutes.
First, we must let:
x = number of tickets intended for adults
y = number of tickets intended for children.
a. Write in terms of x the number of tickets for children
Solution:
x + y = 28 ⇔ y = 28 - x (equation 1)
To answer in terms of x:
no. of tickets for tickets for children = 28 - x
b. the amount spent on tickets for adults
Solution: $30 is the cost of ticket per adult and there are x number of tickets intended for adults.
Therefore,
amount spent on ticket for adults = 30x
c. the amount spent on the tickets.
Solution:
$ 15 = cost of ticket per child
$ 30 = cost of ticket per adult
total amount spent on tickets = 30x + 15y ⇒ (equation2)
substitute equation 1 to equation 2.
(equation 1) y = 28 - x
(equation 2) total amount spent on tickets = 30x + 15y
total amount spent on tickets = 30x + 15(28-x)
total amount spent on tickets = 30x + 420 - 15x
total amount spent on tickets = 15x + 420
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Answer: A - sin 63
Step-by-step explanation:
