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2 years ago

3, -2, -7,... what is the common difference of this arithmetic sequence

Mathematics

1 answer:

worty [1.4K]2 years ago

7 0

Answer: -5

Step-by-step explanation: The common difference is the same number we are adding each time to get from one term to the next.

In this sequence, we are adding -5 each time

so our common difference is -5.

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The radioactive isotope radium has a half-life of 1,600 years. The mass of a 100-gram sample of radium will be______ grams after

Olenka [21]

To solve this we are going to use the half life equation $N(t)=N_{0} e^{( \frac{-0.693t}{t _{1/2} }) }$
Where:
$N_{0}$ is the initial sample
$t$ is the time in years
$t_{1/2}$ is the half life of the substance
$N(t)$ is the remainder quantity after $t$ years

From the problem we know that:
$N_{0} =100$
$t=200$
$t_{1/2} =1600$

Lets replace those values in our equation to find $N(t)$ :
$N(200) =100e^{( \frac{(-0.693)(200)}{1600}) }$
$N(200)=100e^{( \frac{-138.6}{1600} )}$
$N(200)=100e^{-0.086625}$
$N(200)=91.7$

We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be 91.7 grams.

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2 years ago

Which is the graph of the equation y-1=2/3(x-3)? PLEASE ANSWER ASAP

alexgriva [62]

Answer:

Graph #1

Step-by-step explanation:

Compare your

y - 1 = (2/3)(x - 3) to

y - k = m(x - h). We see that k = 1 and h = 3.

Thus, (1, 3) is a point on the graph. This matches Graph #1.

Note: Graph #1 and Graph #3 appear to be the same. Why?

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2 years ago

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How many 2/3 cups are there in 6 cups

xeze [42]

Answer: 9
Divide 6 by 2/3

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2 years ago

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if alyssa plans to run 7/8 mile on a trail at one point she sees that she is at mile maker 0.3 How much farther does she have to

Sever21 [200]

Rewrite 7/8 as a decimal by dividing 7 by 8:

7/8 = 0.875

Now to find how much further she has to run subtract where is now from the total distance:

0.875 - 0.3 = 0.575

She needs to run 0.575 miles more

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2 years ago

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the n

Ivanshal [37]

Answer:

a) The probability that exactly 4 flights are on time is equal to 0.0313

b) The probability that at most 3 flights are on time is equal to 0.0293

c) The probability that at least 8 flights are on time is equal to 0.00586

Step-by-step explanation:

The question posted is incomplete. This is the complete question:

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded. Round answers to 3 significant figures.

a) The probability that exactly 4 flights are on time is =

b) The probability that at most 3 flights are on time is =

c)The probability that at least 8 flights are on time is =

<h2>Solution to the problem</h2>

a) Probability that exactly 4 flights are on time

Since there are two possible outcomes, being on time or not being on time, whose probabilities do not change, this is a binomial experiment.

The probability of success (being on time) is p = 0.5.

The probability of fail (note being on time) is q = 1 -p = 1 - 0.5 = 0.5.

You need to find the probability of exactly 4 success on 9 trials: X = 4, n = 9.

The general equation to find the probability of x success in n trials is:

$P(X=x)=_nC_x\cdot p^x\cdot (1-p)^{(n-x)}$