Ask question

Ask question

All categories

3 years ago

7

the formula a= vf-v1 is used to calculate acceleration as the change in velocity over a period of time. solve the formula for th

e final velocity, vf in terms of initial velocity, v1, acceleration, a, and time,

1 answer:

KatRina [158]3 years ago

8 0

Answer : vf=at+v1

Step-by-step explanation:

a=(vf-v1)/t

at=vf-v1

at+v1=vf

You might be interested in

Analyze the key features of the graph of f(x) shown below.

melomori [17]

Answer:

y= -2 + 1/(3+x)

If you want to check just plug it into a graphing calculator.

3 0

3 years ago

(7x-14)<br> (4x + 19)<br> What’s the value of x

erastovalidia [21]

Answer:

Step-by-step explanation:

( 7x - 14 ) ( 4x + 19 )

28x^2 - 133x - 56x - 416

= 28x^2 - 189x - 416

7 0

4 years ago

1.13-lab: temperature of soil and water

Schach [20]

Radiation from the sun heats the Earth's surface by means of rays that are trapped in the atmosphere and allow the Earth to have constant heat.

<h3>How is the Earth's surface heated?</h3>

The surface of the Earth heats up due to the sun's rays that hit it and when they enter the atmosphere they are reflected on the surface being trapped between the atmosphere and the surface.

Another important aspect to keep in mind is that the rays strike at different angles throughout the Earth, for example:

In the equatorial zone they affect directly, so this zone tends to be more quality than others in which the rotation and translation of the Earth cause the rays to enter in less or more quantity throughout the year.

Learn more about solar rays in: brainly.com/question/919704

5 0

2 years ago

a person kicks a ball from the ground into the air with an initial upward velocity of 8 feet per second. what is the maximum hei

KengaRu [80]

Chech the picture below.

if the person kicked it from the ground, that means its initial height is 0.

it reaches its maximum height at the y-coordinate of its vertex, and it will hit the ground when y = 0, as you see in the picture.

$\bf ~~~~~~\textit{initial velocity}
\\\\
\begin{array}{llll}
~~~~~~\textit{in feet}
\\\\
h(t) = -16t^2+v_ot+h_o
\end{array} 
\quad 
\begin{cases}
v_o=\stackrel{8}{\textit{initial velocity of the object}}\\\\
h_o=\stackrel{0}{\textit{initial height of the object}}\\\\
h=\stackrel{}{\textit{height of the object at "t" seconds}}
\end{cases}
\\\\\\
h(t)=-16t^2+8t+0$

now let's find the y-coordinate of its vertex

$\bf \textit{vertex of a vertical parabola, using coefficients}
\\\\
h(t)=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+8}t\stackrel{\stackrel{c}{\downarrow }}{+0}
\qquad \qquad 
\left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)
\\\\\\
\left(\qquad ,~~0-\cfrac{8^2}{4(-16)} \right)\implies (\quad ,~0+1)\implies (\quad ,~1)$

when will it hit the ground?

$\bf \stackrel{h(t)}{0}=-16t^2+8t\implies 16t^2-8t=0\implies 8t(2t-1)=0
\\\\\\
8t=0\implies \stackrel{\textit{0 seconds when it took off first}}{t=0}
\\\\\\
2t-1=0\implies 2t=1\implies \stackrel{\textit{half a second later it when it came back down}}{t=\cfrac{1}{2}}$

3 0

3 years ago

dimaraw [331]

32, i believe is the answer

5 0

4 years ago