Answer:
The fraction is 1/4
Step-by-step explanation:
we know that
The area of an equilateral triangle, using the law of sines is equal to



where
x is the length side of the triangle
In this problem
Let
b ----> the length side of the regular hexagon
2b ---> the length side of the equilateral triangle
step 1
Find the area of the six triangles
Multiply the area of one triangle by 6
![A=6[x^{2}\frac{\sqrt{3}}{4}]](https://tex.z-dn.net/?f=A%3D6%5Bx%5E%7B2%7D%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%5D)

we have

substitute

step 2
Find the area of the regular hexagon
Remember that, a regular hexagon can be divided into 6 equilateral triangles
so
The area of the regular hexagon is the same that the area of 6 equilateral triangles

we have

substitute

step 3
To find out what fraction of the total area of the six triangles is the area of the hexagon, divide the area of the hexagon by the total area of the six triangles

Answer:
939,520 would be the answer. You're rounding the 15 part up to the next ten which would be 20, making the answer 939,520.
Answer:
The mean is 6.6
The median is 16
mode is 18
Step-by-step explanation:
I'm not sure if this is tight but yeah:)
The margin of error given the proportion can be found using the formula

Where

is the z-score of the confidence level

is the sample proportion

is the sample size
We have



Plugging these values into the formula, we have:

The result 0.14 as percentage is 14%
Margin error is 38% ⁺/₋ 14%