Question

There are 8 midsize cars and 15 compact cars and 6 will be selected. What is the probability of selecting all midsize cars?

Answer 1

Answer:

Assuming order does not matter, the probability of selecting all midsize cars is 0.000277373, or $\frac{4}{14421}$.

Step-by-step explanation:

First, we must find the n(Total arrangements of selections)=(8+15)C6

n(Total arrangements of selections)=23C6

n(Total arrangements of selections)=100,947

Second, we must find the n(Arrangements where all are midsize cars)=8C6

n(Arrangements where all are midsize cars)=28

To find the probability of selecting all midsize cars, we divide the n(Arrangements where all are midsize cars) by the n(Total arrangements of selections):

P(All midsize cars)= $\frac{28}{100,947}$

P(All midsize cars)= $\frac{4}{14421}$=0.000277373.