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3 years ago

Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!

Mathematics

1 answer:

Misha Larkins [42]3 years ago

3 0

Answer:

(-2.5, 1) and (0.5, 5)

Step-by-step explanation:

The main idea is to divide the line into four segments.

so you find the midpoint between (-4, -1) and (2, 7), which is (-1, 3).

then you find the midpoint again between (-4, -1) (-1, 3) and (2, 7) (-1, 3), which is (-2.5, 1) and (0.5, 5).

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Help plz

zvonat [6]

Answer:

1) -5

2) 5

3) -4

4) 7

5) 3

Step-by-step explanation:

1) -20 divided by -4

2) -2 plus 7

3) 20 divided by 5

4) -2 plus 9

5) 20 minus 17

3 0

3 years ago

Read 2 more answers

Can I have help I am stuck on this problem It would mean the world if u helped me and tysm!! =-)

Leona [35]

Answer : 424.875 miles

The problem states that Brian can travel ‘27.5’ miles per gallon, and his tank can only hold ‘15.45’ gallons of fuel.

To find the miles he can travel, all you have to do is multiply the miles he can travel per gallon (27.5) by the gallons he has in the tank (15.45).

This gives you the answer of 424.875 miles.

4 0

3 years ago

Read 2 more answers

HELP WITH ALL <br> Determine the composite functions of the following set of functions

elixir [45]

QUESTION 1

i) Given $f(x)=5x-2$ and $g(x)=x^2$ .

$(f\circ g)=f(g(x))$

$(f\circ g)=f(x^2)$

We plug in $x^2$ into $f(x)=5x-2$

$(f\circ g)=5x^2-2$

ii) Given $f(x)=5x-2$ and $g(x)=x^2$ .

$(g\circ f)=g(f(x))$

$(g\circ f)=g(5x-2)$

We plug in $5x-2$ into $g(x)=x^2$

$(g\circ f)=(5x-2)^2$

$(g\circ f)=25x^2-10x-10x+4$

$(g\circ f)=25x^2-20x+4$

QUESTION 2

i) Given $g(x)=x^2-4$ and $h(x)=\sqrt{2x+1}$ .

$(h\circ g)=h(g(x))$

$(h\circ g)=h(x^2-4)$

We plug in $x^2-4$ into $h(x)=\sqrt{2x+1}$

$(h\circ g)=\sqrt{2(x^2-4)+1}$

$(h\circ g)=\sqrt{2x^2-8+1}$

$(h\circ g)=\sqrt{2x^2-7}$

ii) Given $g(x)=x^2-4$ and $h(x)=\sqrt{2x+1}$ .

$(g\circ h)=g(h(x))$

$(g\circ h)=g(\sqrt{2x+1})$

We plug in $\sqrt{2x+1$ into $g(x)=x^2-4$

$(g\circ h)=(\sqrt{2x+1})^2-4$

$(g\circ h)=2x+1-4$

$(g\circ h)=2x-3$

QUESTION 3

i) Given $g(x)=x+5$ and $h(x)=\sqrt{x-4}$ .

$(g\circ h)=g(h(x))$

$(g\circ h)=g(\sqrt{x-4})$

We plug in $\sqrt{x-4}$ into $g(x)=x+5$

$(g\circ h)=\sqrt{(x-4)+5}$

ii) Given $g(x)=x+5$ and $h(x)=\sqrt{x-4}$ .

$(g\circ g)=g(g(x))$

$(g\circ g)=g(x+5)$

We plug in $x+5$ into $g(x)=x+5$

$(g\circ g)=(x+5)+5}$

$(g\circ g)=x+10}$

QUESTION 4

The given functions are;

$f(x)=-2x+1$ and $g(x)=-x^2$

$f\circ f=f(f(x))$

$f\circ f=f(-2x+1)$

$f\circ f=-2(-2x+1)+1)$

$f\circ f=4x-2+1)$

$f\circ f=4x-1)$

ii)

$g\circ g=g(g(x))$

$g\circ g=g(-x^2)$

$g\circ g=-(x^2)^2$

$g\circ g=-x^4$

QUESTION 5

$f(x)=5x-2;g(x)=x^2;h(x)=-3x$

$h\circ g\circ f=h\circ (g(f(x))$

$h\circ g\circ f=h\circ (g(5x-2))$

$h\circ g\circ f=h\circ ((5x-2)^2)$

$h\circ g\circ f=h\circ (25x^2-20x+4)$

$h\circ g\circ f=h(25x^2-20x+4)$

$h\circ g\circ f=-3(25x^2-20x+4)$

$h\circ g\circ f=-75x^2+60x-12)$

ii.

$f\circ f\circ g=f\circ (f(g(x))$

$f\circ f\circ g=f\circ (f(x^2)$

$f\circ f\circ g=f\circ (5x^2-2)$

$f\circ f\circ g=f(5x^2-2)$

$f\circ f\circ g=5(5x^2-2)-2$

$f\circ f\circ g=25x^2-10-2$

$f\circ f\circ g=25x^2-12$

7 0

3 years ago

6x^2 - 9x + 3<br> - (8x²+ 7x - 1)

Solnce55 [7]

Answer:

-2x² - 16x + 4

Step-by-step explanation:

Step 1: Write out expression

6x² - 9x + 3 - (8x² + 7x - 1)

Step 2: Distribute negative

6x² - 9x + 3 - 8x² - 7x + 1

Step 3: Combine like terms (x²)

-2x² - 9x + 3 - 7x + 1

Step 4: Combine like terms (x)

-2x² - 16x + 3 + 1

Step 5: Combine like terms (constants)

-2x² - 16x + 4

8 0

3 years ago

Read 2 more answers

Choose the correct first step(s) to solve the system using elimination. 4x + 7y = 6 and 6x + y = 2

exis [7]

$\left\{\begin{array}{ccc}4x+7y=6\\6x+y=2&|multiply\ both\ sides\ by\ (-7)\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}4x+7y=6\\-42x-7y=-14\end{array}\right}\\.\ \ \ -38x=-8$

7 0

4 years ago