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3 years ago

Math IIIB Performance Task: Piecewise-Defined Functions

Mathematics

1 answer:

meriva3 years ago

7 0

9514 1404 393

Explanation:

a) see the attachment for a graph (red curve)

b) The piecewise defined function can be ...

$\displaystyle C(x)=\begin{cases}0&0\le x\le 1\\5&1$

c) The new cost function is ...

$\displaystyle C(x)=\begin{cases}10&0\le x\le5\\x+5&5$

The charge is a flat $10 for any period up to 5 hours, then $1 per additional hour after that, prorated for partial hours. There is apparently no upper limit on parking time as there was with the original function. (The graph shown goes beyond 15 hours; the domain of the original C(x) is 0 to 12 hours.) For reference, the new cost structure is shown in blue in the attachment.

_____

Additional comment

Under the new structure, costs are significantly higher for short-term parking, and lower once the term exceeds 6 hours.

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Write the frost ten terms of a sequence whose first term is -10 and whose common difference is -2

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Answer:

$-10,-12,-14,-16,-18,-20,-22,-24,-26,-28,...$

Step-by-step explanation:

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant, called the common difference

The formula for an Arithmetic Sequence is equal to

$a_n=a_1+(n-1)d$

where

d is the common difference

n is the number of terms

a_1 is the first term of the sequence

In this problem we have

$a_1=-10\\d=-2$

substitute

$a_n=-10+(n-1)(-2)$

$a_n=-10-2n+2$

$a_n=-2n-8$

Find the first ten terms

$a_1=-10$

For n=2 ----> $a_2=-2(2)-8=-12$

For n=3 ----> $a_3=-2(3)-8=-14$

For n=4 ----> $a_4=-2(4)-8=-16$

For n=5 ----> $a_5=-2(5)-8=-18$

For n=6 ----> $a_6=-2(6)-8=-20$

For n=7 ----> $a_7=-2(7)-8=-22$

For n=8 ----> $a_8=-2(8)-8=-24$

For n=9 ----> $a_9=-2(9)-8=-26$

For n=10 ----> $a_1_0=-2(10)-8=-28$

The sequence is

$-10,-12,-14,-16,-18,-20,-22,-24,-26,-28,...$

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Step-by-step explanation:

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Answer:

Class interval ____, Frequency _ C/frequency

1 - 10 ____________ 1 _________ 1

11 - 20 ___________ 4 _________ 5

20 - 30 __________ 6 _________ 11

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41 - 50 ___________ 1 _________ 15

51 - 60 ___________ 1 _________ 16

Step-by-step explanation:

Given the data :

35, 26, 31, 17, 46, 30, 28, 21, 26, 34, 15, 27, 7, 18, 16, 57

Class interval ____, Frequency _ C/frequency

1 - 10 ____________ 1 _________ 1

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20 - 30 __________ 6 _________ 11

31 - 40 ___________3 _________ 14

41 - 50 ___________ 1 _________ 15

51 - 60 ___________ 1 _________ 16

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Answer:

1. Yes

2. No

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4. No

5. Yes

Step-by-step explanation:

Do you mean equal proportion?

1. 3 : 9 = 6 : 18 TRUE because 3 : 9 = 1 : 3 and 6 : 18 = 1 : 3

2. 28 : 7 = 64 : 16 FALSE because they are just not related.

3. 95 : 100 = 17 : 20 FALSE because the closest they get are 19 : 20 ≠ 17 : 20

4. 60 : 80 = 14 : 16 FALSE because the closest they get are 60 : 80 = 6 : 8 and 14 : 16 = 7 : 8

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