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Sonbull [250]
3 years ago
13

How do I answer question b?

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
7 0
The answer for that would be 2 raise to 5. solution:

2 ³ x 2 raise to 6 = 2 raise to 9
thus, you have now, 
2 raise to 9 over 2 raise to 4

subtracting 4 from 9
the Answer is 2 raise to 5
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In the diagram, point D divides line segment AB in the ratio of 5:3. If line segment AC is vertical and line segment CD is horiz
KIM [24]

Answer:

D

Step-by-step explanation:

First, find the coordinates of pointD if A(2,-6), B(10,2) and point D divides line segment AB in the ratio of 5:3.

If point D divides the segment AB in the ratio m:n, then

D\left(\dfrac{nx_A+mx_B}{m+n},\dfrac{ny_A+my_B}{m+n}\right)

So

D\left(\dfrac{3\cdot 2+5\cdot 10}{5+3},\dfrac{3\cdot (-6)+5\cdot 2B}{5+3}\right)=D(7,-1)

Point C has the x-coordinate the same as point A and the y-coordinate the same as point D.

Thus, C(2,-1)

5 0
3 years ago
Read 2 more answers
Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least
Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

<u><em>1) The probability of having a face card in the first turn</em></u>

In this case, the chances are 12 in 52:

P_1=P(face\, card)=12/52=0.231

<u><em>2) The probability of having a face card in the second turn, having a non-face card in the first turn.</em></u>

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181

<u><em>3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.</em></u>

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141

<u><em>4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.</em></u>

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109

With these four probabilities we can calculate the probability of losing this bet:

P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

P=P_1+P_2+P_3=0.231+0.181+0.141=0.553

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

5 0
3 years ago
2. Solve by finding square roots. 9x^2 = 25
Verdich [7]
The answers B !!!!!!!
3 0
2 years ago
Find the equation of the tangent at ( 0 , 2) to the circle with equation
Leto [7]
Https://www.cymath.com/answer?q=(x%20%2B%202)%20%5E%202%20%2B%20(y%20%2B%201)%20%5E%202%20%3D%2013
Just go here
7 0
2 years ago
What is the rate of change <br> x y<br> -2 -6<br> -1 -3<br> 0 0
Natalka [10]
So you subtract their integers by starting from the bottom then coming up to the top. And you just put the numbers in your calculator. Once you’ve got your answer for X and Y, you multiply them both. Which will give you -9/3. Next you divide -9 by 3 and 3 divided by 3. Which will give you -3/1 and just rewrite it as -3. I don’t know if this helps but I hope it does :).
5 0
3 years ago
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