Which graph represents the function y= 1/4×

Given the situation, which inequality models the number of additional weeks marie needs to continue saving to afford the home re

Artemon [7]

In the inequality models, the number of additional weeks is 1558+60x≥2158.

Given that the initial savings is $1558, the amount needed is $2158 and additional savings is $60 weekly.

Let the number of weeks be x.

So, she will save 60x in x weeks.

Total savings after x weeks is

Initial saving +60x .......(1)

According to the question, she needs $1258 for repair.

So, that means the minimum requirement is 2158.

≥2158 ........(2)

Combine equations (1) and (2) and get

Initial savings +60x≥2158

As given that the initial savings is 1558.

Substitute this in above inequality and get

1558+60x≥2158

To find the number of weeks find value of x.

Subtract 1558 from either sides of the inequality.

1558+60x-1558≥2158-1558

60x≥600

Divide both sides with 60 as

60x÷60≥600÷60

x≥10

Hence, the inequality that models the number of additional weeks marie needs to continue saving to afford the home repairs is 1558+60x≥2158 and she needs to save $60 for at least 10 weeks.

Learn about inequality from here brainly.com/question/9774970

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6 0

3 years ago

______________ is the only operation performed in distributive property. ? Help!

valentina_108 [34]

Answer:distributing is the only operation performed in distributive property.

Step-by-step explanation:

4 0

3 years ago

Following diagram find the missing measure.

Temka [501]

Answer:

B

Step-by-step explanation:

The diagram basically shows three angles that make up a straight line.

We know the angle of a straight line is 180°.

Since there are three angles, Angle 1, Angle 2, and Angle 3 that make up a straight line, we can write:

Angle 1 + Angle 2 + Angle 3 = 180

3x + 4x + 2x = 180

9x = 180

x = 180/9

x = 20

The correct answer is B

7 0

3 years ago

A fair die is cast four times. Calculate

azamat

Answer:

I'd say that is an "occupancy problem".

I ran a spreadsheet simulation of that and I'd say the probability is approximately .13

Those problems are rather complex to solve. What I think you would have to do is calculate the probability of

A) ZERO sixes appearing in 4 rolls.

B) exactly 1 six appears in 4 rolls.

C) exactly 2 sixes appear in 4 rolls.

D) exactly 3 sixes appear in 4 rolls. and

E) exactly 4 sixes appear in 4 rolls.

4 rolls of a die can produce 6^4 or 1,296 combinations.

A) is rather easy to calculate: The probability of NOT rolling a six in one roll is 5/6. In 4 rolls it would be (5/6)^4 = 0.4822530864

E) is fairly easy to calculate: The probability of rolling one six is (1/6). The probability of rolling 4 sixes is (1/6)^4 = 0.0007716049

Then we need to:

D) calculate how many ways can we place 3 objects into 4 bins

C) calculate how many ways can we place 2 objects into 4 bins

B) calculate how many ways can we place 1 objects into 4 bins

I don't know how to calculate D C and B

Step-by-step explanation:

3 0

4 years ago

Consider a drug testing company that provides a test for marijuana usage. Among 317 tested subjects, results from 25 subjects w

svet-max [94.6K]

Answer:

We conclude that we fail to reject $H_0$ as there is not sufficient evidence to warrant support of the claim that less than 10 percent of the test results are wrong.

Step-by-step explanation:

We are given that among 317 tested subjects, results from 25 subjects were wrong.

We have to test the claim that less than 10 percent of the test results are wrong.

Let p = proportion of subjects that were wrong.

So, Null Hypothesis, $H_0$ : p = 10% {means that 10 percent of the test results are wrong}

Alternate Hypothesis, $H_A$ : p < 10% {means that less than 10 percent of the test results are wrong}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p (1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of test results that were wrong = $\frac{25}{317}$ = 0.08

n = sample of tested subjects = 317

So, test statistics = $\frac{0.08-0.10}{\sqrt{\frac{0.08 (1-0.08)}{317} } }$

= -1.31

The value of z test statistics is -1.31.

Now, the P-value of the test statistics is given by the following formula;

P-value = P(Z < -1.31) = 1 - P(Z $\leq$ 1.31)

= 1 - 0.9049 = 0.095

Now, at 0.05 significance level the z table gives critical value of -1.645 for left-tailed test. Since our test statistics is more than the critical value of z as -1.31 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that we fail to reject $H_0$ as there is not sufficient evidence to warrant support of the claim that less than 10 percent of the test results are wrong.

5 0

3 years ago

Which graph represents the function y= 1/4× - 3