Both of these problems will be solved in a similar way, but with different numbers. First, we set up an equation with the values given. Then, we solve. Lastly, we plug into the original expressions to solve for the angles.
[23] ABD = 42°, DBC = 35°
(4x - 2) + (3x + 2) = 77°
4x+ 3x + 2 - 2 = 77°
4x+ 3x= 77°
7x= 77°
x= 11°
-
ABD = (4x - 2) = (4(11°) - 2) = 44° - 2 = 42°
DBC = (3x + 2) = (3(11°) + 2) = 33° + 2 = 35°
[24] ABD = 62°, DBC = 78°
(4x - 8) + (4x + 8) = 140°
4x + 4x + 8 - 8 = 140°
4x + 4x = 140°
8x = 140°
8x = 140°
x = 17.5°
-
ABD = (4x - 8) = (4(17.5°) - 8) = 70° - 8° = 62°
DBC =(4x + 8) = (4(17.5°) + 8) = 70° + 8° = 78°
Answer:
D. 99
Step-by-step explanation:
Well they were losing money so 11 times 9 = 99
Answer: IXL
Step-by-step explanation:
Answer:
a)0.6192
b)0.7422
c)0.8904
d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Step-by-step explanation:
Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then
z(p)=
where
- Me is the margin of error from the mean
- s is the standard deviation of the population
a.
z(p)=
≈ 0.8764
by looking z-table corresponding p value is 1-0.3808=0.6192
b.
z(p)=
≈ 1.1314
by looking z-table corresponding p value is 1-0.2578=0.7422
c.
z(p)=
≈ 1.6
by looking z-table corresponding p value is 1-0.1096=0.8904
d.
Minimum required sample size for 0.95 probability is
N≥
where
- z is the corresponding z-score in 95% probability (1.96)
- s is the standard deviation (50)
- ME is the margin of error (8)
then N≥
≈150.6
Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.
Answer:
it took her 54 mins to finish her walk.
Step-by-step explanation:
Given;
total distance walked by Katie, d = ⁵/₆
time taken to walk ¹/₆ mile = 10 mins
break time = 1 min
There are five ¹/₆ mile in the total distance which is ⁵/₆ miles.
Time for the first ¹/₆ mile = 10 mins +
break time = 1 min
Time for the second ¹/₆ mile = 10 mins +
break time = 1 min
Time for the third ¹/₆ mile = 10 mins +
break time = 1 min
Time for the fourth ¹/₆ mile = 10 mins +
break time = 1 min
Time for the fifth ¹/₆ mile = 10 mins
Total time = 5 (10 mins) + 4 (1 min)
= 50 mins + 4mins
= 54 mins
Therefore, it took her 54 mins to finish her walk.
