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mihalych1998 [28]
3 years ago
14

Please help me, please

Mathematics
1 answer:
AlladinOne [14]3 years ago
6 0

Answer:

9\pi \:  (x - {4})^{2}

9π ( x - 4

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I don't know how to do please let me I will try solve the question

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2 years ago
Help it’s homework!!!!
Airida [17]

Answer:

(3x - 3)(x + 2)

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3x^2 + 3x - 6

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3x(x + 2) -3(x + 2)

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3 years ago
Some friends of yours collected books for a book drive. They collected 64 Fiction, and 48 Non-Fiction books. They asked you to m
Cloud [144]

As all of the bundles have the same content inside, so assuming that there is x number of Fiction books and y number of Non-fiction books in each bundle.

Let n be the total number of bundles that my team can send.

There are 64 Fiction books, so

nx=64 ...(i)

Or x=64/n ...(ii)

also, there are 48 Non-Fiction books, so

ny=48 ...(iii)

Or y=48/n ...(iv)

Observing that the numbers x, y, and n are counting numbers and from equations (i) and (iii), n is the common factor of 64 and 48.

The possible common factors of 64 and 48 are,

n=1,2,4,8, and 16.

So, my team can send 1,2,3,4,8 or 16 bundles of books.

Now, from equations (ii) and (iv),

For n=1:

x=64/1=64

y=48/1=48

So, for 1 bundle the number of Fiction and Non-fictions books are 64 and 48 respectively.

For n=2:

x=64/2=32

y=48/2=48

So, for 2 bundles, the number of Fiction and Non-fictions books are 32 and 24 respectively.

For n=4:

x=64/4=16

y=48/4=12

So, for 4 bundles, the number of Fiction and Non-fictions books are 16 and 12 respectively.

For n=8:

x=64/8=8

y=48/8=6

So, for 8 bundles, the number of Fiction and Non-fictions books are 8 and 6 respectively.

For n=16:

x=64/16=4

y=48/16=3

So, for 16 bundles, the number of Fiction and Non-fictions books are 4 and 3 respectively.

8 0
3 years ago
What is the measure of the indicated angle?<br> A 180°<br> B 110°<br> C 70°<br> D 90°
ikadub [295]

Answer:

D. 70°

Step-by-step explanation:

the sum of the unknown angle and 110° is 180 °

so, let the unknown angle be x

x+110 = 180

x = 180-110

x = 70°

8 0
2 years ago
The reading speed of second grade students in a large city is approximately​ normal, with a mean of 90 words per minute​ (wpm) a
Genrish500 [490]
The probability is 0.2743.

Calculating the z-score for this time, we have:

z = (X-μ)/σ
z = (96-90)/10 = 6/10 = 0.6

Using a z-table (http://www.z-table.com) we see that the area to the left of this, less than this score, is 0.7257.  This means the area greater than this would be 1-0.7257 = 0.2743.
6 0
3 years ago
Read 2 more answers
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