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3 years ago

Question 22 of 43

Mathematics

2 answers:

tensa zangetsu [6.8K]3 years ago

8 0

Answer:

the base of the parallelogram is apoplexy equal to the half the circumles of the circle D

Step-by-step explanation:

Wittaler [7]3 years ago

7 0

Answer: D. Half of the Circumference

Step-by-step explanation:

I just got it right on my quiz so its ap3x approved.

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The complement to an angle with a measure of 53 degrees is 27 degrees.<br><br> is this true or false

Arlecino [84]

It is true
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3 years ago

What is the circumference, in centimeters, of the circle? Use 3.14 for Pi, show the equation you use as well.

madreJ [45]

Answer:

C≈113.1

Step-by-step explanation:

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3 years ago

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Elijah has saved $10. He wants to buy shoes for $14. That would make his money situation to be.

murzikaleks [220]

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4 years ago

Integrate the following

enot [183]

I suppose you mean to have the entire numerator under the square root?

$\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx$

We can use a trigonometric substitution to start:

$x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt$

Then for $x=2$ , $t=\sec^{-1}1=0$ ; for $x=4$ , $t=\sec^{-1}2=\frac\pi3$ . So the integral is equivalent to

$\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt$

We can write

$\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t$

so the integral becomes

$\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}$

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3 years ago

Find the total value of digit 3 in 3654

aivan3 [116]

Answer:

3000

Step-by-step explanation:

Thousands Hundreds Tens Ones

3 6 5 4

Here are the values of each number:

Number x Multiplier = Value

3 x 1,000 3,000

6 x 100 600

5 x 10 50

4 x 1 4

Add up all of the values and you get 3,654.

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3 years ago

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