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kipiarov [429]
3 years ago
10

What is 3 2/6 - 2/3??

Mathematics
2 answers:
Butoxors [25]3 years ago
8 0

Answer:

16/6 or 2 2/3

Step-by-step explanation:

Hi,

First, start off by writing 3 2/6 as an improper fraction. To do this, multiply the denominator by the whole number and add the numerator...

6 x 3 = 18 + 2 = 20

3 2/6 = 20/6

20/6 - 2/3

Now, get common denominators.

2/3 X 2/2 = 4/6

20/6 - 4/6 = 16/6

Your answer is 16/6 or 2 4/6 which simplifies to 2 2/3

Hope this helps :)

drek231 [11]3 years ago
3 0

Answer:

14/3

Step-by-step explanation:

32/6 - 2/3

16/3 - 2/3

16-2/3

14/3

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Check the picture below.

a)

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let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

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\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
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\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
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\\\\\\
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b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.


\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
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\end{array}\\\\
-------------------------------

\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
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