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Elenna [48]
3 years ago
8

What is the third derivative of tan x?

Mathematics
1 answer:
azamat3 years ago
4 0
The First is sec^2(x). Second is 2sec^2tanx. From that you get 2[2sec^2xtan^x+sec^4x]
You might be interested in
5000 is 1/10 of what
VikaD [51]
50,000 is the answer because if you multiply 5,000 and 10 you get 50,000. And if you divide 50,000 by 10 you get 5,000. Which is 1/10 of 50,000.
6 0
2 years ago
Write an equation in which the quadratic expression 3x^2+6x-24 equals 0. Show the expression in factored form and explain what y
mr_godi [17]

Answer:

3x² + 6x - 24 = 0

(3x - 6)(x + 4) = 0

x = -4 , x = 2 when y = 0

Step-by-step explanation:

3x² + 6x - 24 = 0

(3x - 6)(x + 4) = 0

Means

3x - 6 = 0 ⇒ 3x = 6 ⇒ x = 6 ÷ 3 = 2

x + 4 = 0 ⇒ x = -4

The Parabola which represents the quadratic equation intersects x-axis at

points (2 , 0) and (-4 , 0)

5 0
3 years ago
How do u factor this
PilotLPTM [1.2K]

You can factor a parabola by finding its roots: if

p(x)=x^2+bx+c

has roots x_1,\ x_2, then you have the following factorization:

p(x) = (x-x_1)(x-x_2)

In order to find the roots, you can use the usual formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

In the first example, this formula leads to

x_{1,2} = \dfrac{-2\pm\sqrt{4+4}}{2} = \dfrac{-2\pm\sqrt{8}}{2} = \dfrac{-2\pm2\sqrt{2}}{2} = 1 \pm \sqrt{2}

So, you can factor

x^2-2x-1 = (x-1-\sqrt{2})(x-1+\sqrt{2})

The same goes for the second parabola.

As for the third exercise, simply plug the values asking

f(1.5)=-5.25

you get

f(-1.5) = 1.5c-3 = -5.25

Add 3 to both sides:

1.5c = -2.25

Divide both sides by 1.5:

c = 1.5

7 0
3 years ago
For each value of y, determine whether it is a solution to 7=y÷4.​
rjkz [21]

Answer:

Step-by-step explanation:

7 = y/4

7*4 = y

y = 28

4 0
3 years ago
Read 2 more answers
Solve this equation for A:A ÷ 2 = 4        A. 2   B. 6   C. 8   D. 4
algol13

Answer:

C) 8

Step-by-step explanation:

A ÷ 2 = 4

Get the 2 and 4 on the same side of the equal sign

A = 2 * 4

Multiply

A = 8

:)

6 0
2 years ago
Read 2 more answers
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