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Elenna [48]
3 years ago
8

What is the third derivative of tan x?

Mathematics
1 answer:
azamat3 years ago
4 0
The First is sec^2(x). Second is 2sec^2tanx. From that you get 2[2sec^2xtan^x+sec^4x]
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Which function has the range (-infinity,-2]U[0,infinity)?
iren [92.7K]

Answer:

B. y=csc(x)-1

Step-by-step explanation:

just got it right!

8 0
3 years ago
Read 2 more answers
☆+☆+☆=18<br>♡+♡+☆=14<br>♤+♤+♡=2<br>♡+♤+☆☆=<br><br>Genius only look closely at the details ​
Dmitriy789 [7]

Answer:

15

Step-by-step explanation:

3 stars = 18

1 star = 6

14-6=8/2 = 4

1 heart = 4

1 spade = -1

4 + -1=  3

3 + (2 stars)

3 + 12 = 15

5 0
3 years ago
NYS COMMON CORE MATHEMATICS CURRICULUM Lesson 17 Date Name Lesson 17 Solutions Eric's father works two part-time jobs, onc in th
Law Incorporation [45]

Answer:

Eric's father work 5 hours each afternoon

Step-by-step explanation:

Let x be the no. of hours Eric's father work each afternoon

He works for hours in morning each day = 3

He works for total hours in morning in 5 days=3 \times 5 = 15

He works for total hours in afternoon in 5 days=5x

We are given that he works a total of 40 hours each 5-day workweek.

ATQ

15+5x=40

5x=25

x=5

Hence Eric's father work 5 hours each afternoon

8 0
3 years ago
Solve the following system
scZoUnD [109]

Answer:

{x = -4 , y = 2 ,  z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer:  {x = -4 , y = 2 ,  z = 1

4 0
3 years ago
Help me with it plizz
Liono4ka [1.6K]
2x + 9 = -65
2x = -65 - 9
2x = -74
x = -74/2
x = -37

So, your final answer is -37

Hope this helps!

3 0
3 years ago
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