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mario62 [17]
3 years ago
11

Line AE and line DF are parallel. If m∠ABG = 11x and m∠HCF = 10x + 9, what is m∠ABG?

Mathematics
2 answers:
Minchanka [31]3 years ago
7 0

Answer:

81

Step-by-step explanation:

x=9

11x=99

11x+ABG=180⁰

ABG=81

ArbitrLikvidat [17]3 years ago
6 0

Answer:

Sorry I just noticed I'm answering another question lol and I don't know how to delete my answer......

I'm Sure Angle ABG is 10

Step-by-step explanation:

9x+10

    -10

---------   you cross out the 10's and are left with 9x

9x

---- Divide 9x with 9x

9x  = x(1)  which equals one

Then you times 10 times x(1)

Which is 10

Hope this helped :)

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