-<img src="https://tex.z-dn.net/?f=%5Csqr%5Csqrt4-x%20%2B%5Csqrt%7B4-x" id="TexFormula1" title="\sqr\sqrt4-x +\sqrt{4-x" alt="\s

What are the zeros of the function f(x)=x^2-2x-15

IRINA_888 [86]

Hello,

f(x)=x²-2x-15=x²-2x+1-16=(x-1)²-16
=(x-1-4)(x-1+4)=(x-5)(x+3)
Zeroes are x=5 or x=-3

4 0

3 years ago

Write the equation of the line that passes through the point (-5,5) and has a slope of -8/5

Free_Kalibri [48]

Answer:

The equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

$y=-\frac{8}{5}x-3$

Step-by-step explanation:

Given

$\left(x_1,\:y_1\right)=\left(-5,5\right)$

$m=\frac{-8}{5}$

Point-Slope Form equation is

$\left(y-y_1\right)=m\left(x-x_1\right)$

$\left(y-5\right)=\frac{-8}{5}\left(x-\left(-5\right)\right)$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$y-5=\frac{-8}{5}\left(x+5\right)$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$y-5=-\frac{8}{5}\left(x+5\right)$

$y-5+5=-\frac{8}{5}\left(x+5\right)+5$

$y=-\frac{8}{5}x-3$

Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

$y=-\frac{8}{5}x-3$

5 0

3 years ago

PLEASE HELP!!

Sav [38]

draw the triangle out and place all your given information in it to solve this.

5 0

3 years ago

here were 84 runners to start a race. in the first half of the race, 13 of them dropped out. in the second half of the race, 14

Gala2k [10]

13+14=27 84-27=57 57 runners finished the race.

8 0

4 years ago

2+2+9x8<br> will give brainliest

ella [17]

Answer:

by folllowing the rules of pemdas we see that 2+2+9x8 is sovled as so:

2+2+9x8

2+2+72

4+72

76

Step-by-step explanation:

5 0

3 years ago

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