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Aleks [24]
3 years ago
14

A salesman sells a car for $37,000 and earns 8.5% commission. How much commission does he earn?

Mathematics
1 answer:
nevsk [136]3 years ago
6 0

Answer:

4,352 dollars

Step-by-step explanation:

You might be interested in
A square and rectangle have the same perimeter.
rewona [7]
Perimeter of rectangle:2(length+width):2(13+7)=40
Perimeter of square:4(length of one side):4(x)=40
X=10
7 0
3 years ago
Which property of soil depends on the size of particles?
seropon [69]

The property of soils which depends on the size of particles is Texture.

<h3>Properties of Soil</h3>

The properties of Soil include colour, odor, temperature, and texture as measured by porosity, mouldability and a host of other texture effects.

  • It is evident that the texture of soil is dependent on the size of the particles as it affects how packed the particles of the soil is.

Read more on properties of soil;

brainly.com/question/26462165

4 0
2 years ago
3 sisters are each 2 years apart in age. the youngest sister is emily, the middle sister is samantha and the oldest sister is la
Bad White [126]
Emily = x
Samantha = x + 2
Lauren = x + 4

x + (x + 2) + (x + 4) = 42

x = 12

Thus: 

Emily = 12
Samantha = 14
Lauren = 16
7 0
3 years ago
What is this answer?
kvasek [131]
I got S > 2
Because you would multiply both sides by two then subtract by twelve
_
3 0
3 years ago
Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es
Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4×(1/2)^{\infty}

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

S_{\infty} = \dfrac{a}{1 - r}

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty}  = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2

La suma al infinito de las áreas de los cuadrados, S_{\infty} = 8 in.²

7 0
3 years ago
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