All categories

3 years ago

12 pleaseeeee help meeeee!

Mathematics

2 answers:

m_a_m_a [10]3 years ago

8 0

B because that person said b and i need points

Alex17521 [72]3 years ago

7 0

Answer:

Step-by-step explanation:

You might be interested in

What is x in the equation above?

abruzzese [7]

Answer:

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Use the formula to find the volume of the prisim

andrey2020 [161]

I believe it’s C sorry if I’m wrong

4 0

3 years ago

Read 2 more answers

Can someone help me solve this differentiation/tangent problem?

nirvana33 [79]

A)

$\bf g'(x)=\stackrel{product~rule}{2x\cdot f(x)+x^2\cdot f'(x)}\quad 
\begin{cases}
x=5\\
f(5)=5\\
f'(5)=5
\end{cases}
\\\\\\
g'(5)=2(5)\cdot f(5)+(5)^2\cdot f'(5)\implies g'(5)=50+500\\\\\\ g'(5)=550\\\\
-------------------------------\\\\
g(5)=(5)^2f(5)\implies g(5)=125
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}
\begin{cases}
x=5\\
y=125\\
\stackrel{m}{g'(5)}=550
\end{cases}\implies y-125=550(x-5)
\\\\\\
y-125=550x-2750\implies y=550x+400$

b)

$\bf h'(x)=\stackrel{quotient~rule}{\cfrac{f'(x)(x-6)~~-~~f(x)\cdot 1}{(x-6)^2}}\quad 
\begin{cases}
x=5\\
f(5)=5\\
f'(5)=5
\end{cases}
\\\\\\
h'(5)=\cfrac{f'(5)(5-6)~~-~~f(5)\cdot 1}{(5-6)^2}
\\\\\\
h'(5)=\cfrac{5(-1)-5}{(-1)^2}\implies h'(5)=-10\\\\
-------------------------------\\\\$

$\bf h(5)=\cfrac{f(5)}{5-6}\implies h(5)=\cfrac{5}{-1}\implies h(5)=-5
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\quad 
\begin{cases}
x=5\\
y=-5\\
\stackrel{m}{-10}
\end{cases}\implies y-(-5)=-10(x-5)
\\\\\\
y+5=-10x+50\implies y=-10x+45$

3 0

4 years ago

Given that f (x ) = 5 x - 10 and g (x ) = x = 3 , solve for f (g(x)) when x = -1

svetlana [45]

Answer:

f(g(x))(-1) = 0

Step-by-step explanation:

Step 1: Find f(g(x))

5(x + 3) - 10

5x + 15 - 10

5x + 5

Step 2: Plug in -1

5(-1) + 5

-5 + 5

7 0

3 years ago

What is 5 multiplied by 7

avanturin [10]

Answer:

5x7=35

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers