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galben [10]
4 years ago
14

Can someone help me please

Mathematics
2 answers:
mixas84 [53]4 years ago
8 0

Tyrone:

36x4=204

204>202

tresset_1 [31]4 years ago
7 0

Answer:

Tyrone;204 marbles

Step-by-step explanation:

  • Let Pam’s marbles be x
  • If Tyrone has 6 times as many marbles as Pam=6*x=6x
  • Therefore if Pam has 34 marbles,Tyrone would have 6*34=204 marbles.
  • 204>202 so Tyrone has more marbles.

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5/7 = /14 equivalent fraction answer should be?
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Answer:

the answer I got is false

Step-by-step explanation:

5/7=14 convert 14 to fraction 98/7

5/7=98/7 compare 5/7 and 98/7

so the maths is false question

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3 years ago
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I don’t understand your question
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Part A The year in which the US Civil War ended was 25 percent later than the year Christopher Columbus set sail from Spain. If
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Step-by-step explanation:

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3 years ago
Which equation is perpendicular to 3x - y = 9 and goes through the point (6,6)
Lelechka [254]

Answer:

y = - \frac{1}{3} x + 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 3x - y = 9 into this form by subtracting 3x from both sides

- y = - 3x + 9 ( divide all terms by - 1 )

y = 3x - 9 ← in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{3}, thus

y = - \frac{1}{3} x + c ← is the partial equation

To find c substitute (6, 6) into the partial equation

6 = - 2 + c ⇒ c = 6 + 2 = 8

y = - \frac{1}{3} x + 8 ← equation of perpendicular line

6 0
3 years ago
A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set w
VashaNatasha [74]

Complete Question

A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:

a)F minimum

b) F maximum

c) Frequency resolution

Answer:

a) Fmax=100Hz

b) Fmin=0Hz

c) F_r=0.0313

Step-by-step explanation:

From the question we are told that:

Time t=32sec

FrequencyF=200Hz

Segments \mu=5

Generally the equation for Frequency Range is mathematically given by

Fmax=\frac{F}{2}

Fmax=100Hz

Therefore

a) Fmax=100Hz

b) Fmin=0Hz

c)

Generally the equation for Frequency Resolution is mathematically given by

F_r=\frac{F}{N}

Where

N=The Total dat points

N=Sampling Frequency *Time

N=200*32

N=6400

Therefore

F_r=\frac{200}{6400}

F_r=0.0313

6 0
3 years ago
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