Y = k / x
2 = k / 4
k = 8
Therefore, the answer for this question would be (4,2)
Hello!
Set the two equations equal to each other to solve:
y = -4x + 11
y = 1/2x + 2
-4x + 11 = 1/2x + 2
Add 4x to both sides:
-4x + 4x + 11 = 1/2x + 2 **Convert 4x into 8/2x***
11 = 9/2x + 2
Subtract 2 from both sides:
11 - 2 = 9/2x + 2 - 2
9 = 9/2x
Divide both sides by 9/2:
9 * (2/9) = 9/2x * (2/9)
x = 2.
Answer:
a) what is the probability that Neither will of these products launch ?
= 0.30
b) At least one product will be launched ?
= 0.70
Step-by-step explanation:
From the above question, we have the following information:
P(A) = 0.45
P(B) = 0.60
P(A ∩ B) = P(A and B) launching = 0.35
Step 1
We find the Probability that A or B will launch
P (A ∪ B) = P(A) + P(B) - P(A ∩ B)
= 0.60 + 0.45 - 0.35
= 1.05 - 0.35
= 0.70
a) what is the probability that Neither will of these products launch ?
1 - Probability ( A or B will launch)
= 1 - 0.70
= 0.30
b)At least one product will be launched?
This is equivalent to the probability that A or B will be launched
P (A ∪ B) = P(A) + P(B) - P(A ∩ B)
= 0.60 + 0.45 - 0.35
= 1.05 - 0.35
= 0.70
Answer:
3 5 30 32
Step-by-step explanation:
The question in English is
The age of 4 members of a family adds up to 70. Mom is 6 times bigger than her son and 10 times bigger than her daughter. Dad is 2 years older than Mom. How old are each of the family members? Write the result in ascending order and separated by spaces
Let
x----> Mon's age
y----> Son's age
z----> Daughter's age
w---> Dad's age
we know that
x+y+z+w=70 -----> equation A
x=6y ----> y=x/6 -----> equation B
x=10z ----> z=x/10 -----> equation C
w=2+x -----> equation D
substitute equation B, C and D in equation A and solve for x
x+(x/6)+(x/10)+(2+x)=70
Multiply by 60 both sides
60x+10x+6x+120+60x=4,200
136x=4,200-120
x=4,080/136
x=30 years
Find the value of y
y=x/6 -----> y=30/6=5 years
Find the value of z
z=x/10 ----> z=30/10=3 years
Find the value of w
w=2+x ----> w=2+30=32 years
Write the result in ascending order and separated by spaces
3 5 30 32
so
Daughter Son Mon Dad
