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V125BC [204]
3 years ago
11

A student performed the following steps to solve the equation.

Mathematics
2 answers:
Snezhnost [94]3 years ago
8 0

9514 1404 393

Answer:

  zero, false

Step-by-step explanation:

The equation has <em><u>zero</u></em> solutions because the equation 2=3 is <em><u>false</u></em>.

__

There are no values of the variables that will make that equation true, hence no solutions.

omeli [17]3 years ago
8 0

Answer:

the answer is zero,false

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WILL PICK BRAINLIEST PLZ ANSWER
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Answer:

Archaea

Step-by-step explanation:

Archaea because it can survive in the diverse environments and is distinctly different from Bacteria which can also survive.

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2 years ago
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Question 6 of 10 The triangles shown below may not be congruent. 1) 25° 55° 100° 100° 66° 25° O A. True O B. False​
Blizzard [7]

Answer:

True, they may not be congruent

Step-by-step explanation:

A figure cannot be determined as congruent from three angles alone. In order  for two shapes to be congruent, all corresponding parts must be congruent. This means all the sides and angles of the two shapes must be the same in order for the two shapes to be congruent. If we know all the angles are the same, the sides could still be different lengths, so this does not prove congruency.

5 0
3 years ago
Three billion sixty million sixty six thousand nine hundred ​
Anestetic [448]

Answer:

3,000,000,000

60,000,000

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900

Step-by-step explanation:

3,060,066,900

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8 0
3 years ago
One Sunday, 120 days before Christmas, Aldsworth store publishes an advertisement saying ‘120 shopping days until Christmas'. Al
Lena [83]

Answer:

(a)18

(b)1089

(c)Sunday

Step-by-step explanation:

The problem presented is an arithmetic sequence where:

  • First Sunday, a=1
  • Common Difference (Every subsequent Sunday), d=7

We want to determine the number of Sundays in the 120 days before Christmas.

(a)In an arithmetic sequence:

\text{The nth term}, T_n=a+(n-1)d\\T_n \leq 120\\$Therefore:$\\1+7(n-1) \leq 120\\1+7n-7\leq 120\\7n-6\leq 120\\7n\leq 120+6\\7n\leq 126\\$Divide both sides by 7$\\n\leq 18

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.

Therefore, Aldsworth advertised 18 times.

(b)Next, we want to determine the sum of the first 18 terms of the sequence

1,8,15,...

\text{Sum of a sequence}, S_n=\frac{n}{2}( 2a+(n-1)d)\\S_{18}=\frac{18}{2}( 2*1+(18-1)*7)\\=9(2+17*7)\\=9(2+119)\\=9*121\\S_{18}=1089

The sum of the numbers of days published in all the advertisements is 1089.

(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.

6 0
3 years ago
Please help me find the x and y intercept
Serhud [2]

Answer:

x-intercept(s): (0,0)

y-intercept(s): (0,0)

Step-by-step explanation:

To find the x-intercept(s), substitute in 0 for y and solve for x

0 = -x

To find the y-intercept(s), substitute in 0 for x and solve for y

y = -(0)

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3 years ago
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